我在我的項目管理工具中生成RFP插件。在那個plugIn中,我基本上填寫了一個表格,幾乎沒有usr要求,比如哪個技術有多少資源,時間等... 。如何傳遞嵌套的鍵到rails的對象params
現在填充之後submmitting形式時,假設我填表5場(可能是文本字段,文本區域,布爾型等等...),那麼它submmit 5個問題將被創建
即表單的第1個字段應創建第1個問題
第2個字段的表單應創建第2個問題
,如果我在的形式,然後wont't創建
和問題保持空白的第3場等
我想每個哈希鍵上創建新的問題,如果值是針對perticular關鍵
一個解決方案是,在用戶哈希有來許多關鍵&值填寫表格後,但怎麼可能在不同的每個鍵值,並基於該應用一些循環和創造新的問題
我PARAMS [:USER1]是
{"project_id"=>"first1",
"user1"=>
{"ffval_attributes"=>{"ckval"=>"0"},
"opval_attributes"=>{"ckval"=>"0"},
"jvusedfor"=>"menu sidebar",
"user3_attributes"=>
{"drupal"=>"0",
"wordpress"=>"0",
"joomla"=>"0",
"other2"=>"0",
"Typo3"=>"0"},
"user2"=>
{"cms_ex"=>"ruby", "java"=>"0", "dotnet"=>"0", "other1"=>"1", "php"=>"0"},
"pagenumber_attributes"=>{"uniquepages"=>"3", "subsequentpages"=>"4"},
"gcvals_attributes"=>{"ckval"=>"0"},
"pagetype"=>"false",
"nojavascript"=>"7",
"src_id"=>"",
"numberofmenu"=>"5",
"ss1"=>"0",
"type1"=>"false",
"sfval_attributes"=>{"ckval"=>"0"},
"design_pattern"=>"5",
"dcomplex"=>"no",
"ieval_attributes"=>{"ckval"=>"0"},
"checkpixel"=>"true",
"base"=>"true",
"nohacks"=>"5",
"fuvalue"=>"true",
"mobile"=>"true"},
"utf8"=>"",
"commit"=>"Create User1",
"authenticity_token"=>"UlrGhESPKK6zSr6aL2iIpGt9mR2K5tgBA3NnZP44+XE="}
我試圖在控制器
u = params[:user1]
a = Issue.last
a = a.id
u.each do |key, value|
if value.present?
issue = Issue.new
issue.id = a + 1
**issue.subject = key**
ssue.tracker_id = 1
issue.project_id = 1
issue.priority_id = 2
issue.status_id = 1
issue.author_id = 1
issue.save
a = a + 1
end
我的問題是
如何通過嵌套哈希鍵上issue.subject,如果他們的價值是事先目前 感謝
我努力理解你爲什麼要在這個自定義的方式這樣做的最裏面PARAMS。爲什麼不使用'accep_nested_attributes_for'? http://api.rubyonrails.org/classes/ActiveRecord/NestedAttributes/ClassMethods.html –
它取決於提交的領域的形式!!!!! – Anish