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所以我已經遵循this關於創建自定義ParseQueryAdapter的教程,但由於某種原因,我的列表視圖沒有被填充。ParseQueryAdapter顯示空白列表

列表視圖活動

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_listusers); 

    //Initialize the subclass of PQM 
    listViewAdapter = new ListViewAdapter(this); 

    //Initialize ListView and set view to listadapter 
    usersListView = (ListView) findViewById(R.id.usersListView); 
    usersListView.setAdapter(listViewAdapter); 

ListViewAdapter

public class ListViewAdapter extends ParseQueryAdapter<ParseObject> { 

public ListViewAdapter(Context context){ 
    //Use Query factory to constuct a PQA that will not include the current user 
    super(context, new ParseQueryAdapter.QueryFactory<ParseObject>(){ 
     public ParseQuery create(){ 
      String currentUserId = ParseUser.getCurrentUser().getObjectId(); 
      ParseQuery query = new ParseQuery("User"); 
      query.whereNotEqualTo("objectId", currentUserId); 
      return query; 

     } 
    }); 
} 

//Customise the layout by overriding getItemView 
@Override 
public View getItemView(ParseObject object, View v, ViewGroup parent){ 
    if (v == null){ 
     v = View.inflate(getContext(), R.layout.user_list_items, null); 
    } 

    super.getItemView(object, v, parent); 

    //Add the username textview 
    TextView userListItem = (TextView) v.findViewById(R.id.text1); 
    userListItem.setText(object.getString("username")); 

    //Add the status textview 
    TextView userListSubItem = (TextView) v.findViewById(R.id.userListSubItem); 
    userListSubItem.setText(object.get("status").toString()); 
    return v; 
} 

} 

activity_listusers XML文件

<?xml version="1.0" encoding="utf-8"?> 
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" 
    xmlns:tools="http://schemas.android.com/tools" 
    android:orientation="vertical" 
    android:layout_width="fill_parent" 
    android:layout_height="fill_parent"> 

    <Button 
     android:layout_width="fill_parent" 
     android:layout_height="wrap_content" 
     android:text="@string/logout" 
     android:id="@+id/logoutButton" 
     android:gravity="center_vertical|center_horizontal" 
     android:layout_gravity="center_horizontal" 
     android:background="@color/dark_gray" 
     android:textSize="24sp" 
     android:padding="15dp" 
     android:textColor="@color/heartbeat_red" /> 

    <ListView xmlns:android="http://schemas.android.com/apk/res/android" 
     android:layout_width="match_parent" 
     android:layout_height="match_parent" 
     android:padding="16dp" 
     tools:context="com.sinch.messagingtutorialskeleton.ListUsersActivity" 
     android:background="#ffffff" 
     android:id="@+id/usersListView" 
     > 
    </ListView> 

</LinearLayout> 

User_List_Items XML文件

<?xml version="1.0" encoding="utf-8"?> 

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" 
    android:orientation="vertical" 
    android:layout_width="fill_parent" 
    android:layout_height="fill_parent"> 

    <TextView 
     android:id="@+id/text1" 
     android:textColor="#a9a9a9" 
     android:padding="16dp" 
     android:layout_width="fill_parent" 
     android:layout_height="fill_parent" 
     android:textSize="20sp"> 
    </TextView> 

    <TextView 
     android:id="@+id/userListSubItem" 
     android:textColor="#a9a9a9" 
     android:padding="16dp" 
     android:layout_width="fill_parent" 
     android:layout_height="fill_parent" 
     android:layout_below="@+id/text1" 
     android:textSize="16sp"> 
    </TextView> 

</LinearLayout> 

我對Android相對比較陌生,對Parse也很新,我不知道我哪裏出錯了,Parse可以正常工作,因爲我有一個預先使用Parse登錄的活動。

非常感謝,

編輯:所以我只是在Parse.com創建一個新的類和查詢,代替用戶和哪些工作,不知道如果你不能在用戶類,或者如果使用ParseQueryAdapter我試圖查詢它的方式是錯誤的?

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看起來正確的給我。沒有logcat消息/錯誤? – cYrixmorten 2015-04-05 22:52:16

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也許ParseQuery(「用戶」)應該是ParseQuery(「_ User」) – cYrixmorten 2015-04-05 22:57:00

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@cYrixmorten是的,就是這樣!我沒有意識到,在使用ParseObject時,必須將User類稱爲_User,之前我只使用過ParseUser,但並不確定它可以在使用ParseObject的ParseQueryAdapter的所有教程中使用。謝謝 – 2015-04-05 23:08:54

回答

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感謝@cYrixmorten,構建普通分析查詢時,必須將用戶類稱爲_User。

線從

ParseQuery query = new ParseQuery("User"); 

改變要

ParseQuery query = new ParseQuery("_User");