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Question

請如何寫這個簡單的工作選擇，在Hibernate查詢，或標準

SELECT * FROM `call` AS c JOIN `event_customer` AS e ON c.customer_id = e.customer_id WHERE e.dgdelete = FALSE AND c.eventruletype_id = 1 AND e.event_id = 74 AND c.callactivity_id = 3 AND e.calltype = 2 

我發現已經有很多建議，但沒有任何幫助我呢。

它可能是什麼與Hibernate映射？

謝謝。

PS： 這是行不通的

query = session.createQuery("select c from " + Call.class.getSimpleName()+ " as c " + EventCustomer.class.getSimpleName()+ " as e where e.customer_id = c.customer_id and e.event_id = 74"); 

也是這個工作不

query = session.createQuery("select c from " + Call.class.getSimpleName()+ " as c join " + EventCustomer.class.getSimpleName()+ " as e where e.customer_id = c.customer_id and e.event_id = 74"); 

而且這個

query = session.createQuery("select c from " + Call.class.getSimpleName()+ " as c join " + EventCustomer.class.getSimpleName()+ " as e on e.customer_id = c.customer_id where e.event_id = 74"); 

而且這個

query = session.createQuery("select c from " + Call.class.getSimpleName()+ " as c left join " + EventCustomer.class.getSimpleName()+ " as e on e.customer_id = c.customer_id where e.event_id = 74"); 

，並在某些情況下，我得到這個錯誤

Answer 1

這應該工作。 （用逗號替換JOIN）

Query query = session.createQuery("select c from " + Call.class.getSimpleName() + " as c , " + EventCustomer.class.getSimpleName() + " as e where e.customer.id = c.customer.id and c.event.id = 74"); 

Answer 2

不要連擊，而使用標準：

Criteria crit = session.createCriteria(Call.class, "c") 
    .createCriteria("eventCustomerDto","e") 
    .add(Restrictions.eq("event_id",74)); 
List<Call> list=crit.list(); 

的代碼可能有錯別字，但多數民衆贊成這個想法。另外，對於我的例子，我認爲Call和EventCustomer之間的Call Hibernate映射存在一對多關係。