2017-05-12 33 views
3

我有一個包含天氣數據的字符串。我想爲字符串中的每個值分配一個變量LUA:字符串變量

string = "12-05-17 12:48:48 12.3 23 -8.2 1 2 225 0.0 0.0 992.3 SW 1 m/s C 
hPa mm 49.8 +0.1 0.6 60.0 0.0 21.5 31 12.3 +0.7 13.0 11:31 1.2 01:31 4 10:40 
7 09:36 992.4 12:28 989.4 00:00 1.9.4 1099 6 12.3 12.3 0 0.00 0 176 0.0 24 1 
0 S 2560 m 8.7 0.0 750 0 " 


s1,s2,s3,s4,s5,s6,s7,s8,s9,s10,s11,s12,s13,s14,s15,s16,s17,s18,s19,s20,s21, 
s22,s23,s24,s25,s26,s27,s28,s29,s30,s31,s32,s33,s34,s35,s36,s37,s38,s39,s40, 
s41,s42,s43,s44,s45,s46,s47,s48,s49,s50,s51,s52,s53,s54,s55,s56,s57,s58 = 
response:match(" 
([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s 
([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s 
([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s 
([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s 
([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s 
([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s 
([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s 
([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s([^%s]+)%s 
([^%s]+)%s([^%s]+)") 

Date = s1 
Time = s2 
Temp = s3 
Humidity = sS4 
WindSpeed = s13 
HighTemp = s27 
CloudBase = s53 

但是這不起作用。我收到下面的錯誤消息;

「太多捕獲 棧回溯: 函數 'string.match' main.lua:2:在主要大塊

請幫

+2

58變數,真的嗎?我想你會更好地使用數組。 – lhf

回答

0

可以在結帳我lua-split

的源代碼
local split = require "split" 

local s = "12-05-17 12:48:48 12.3 23 -8.2 1 2 225 0.0 0.0 992.3 SW 1 m/s C hPa mm 49.8 +0.1 0.6 60.0 0.0 21.5 31 12.3 +0.7 13.0 11:31 1.2 01:31 4 10:40 7 09:36 992.4 12:28 989.4 00:00 1.9.4 1099 6 12.3 12.3 0 0.00 0 176 0.0 24 1 0 S 2560 m 8.7 0.0 750 0 " 

local s1,s2,s3,s4,s5,s6,s7,s8,s9,s10,s11,s12,s13,s14,s15,s16,s17,s18,s19,s20,s21, 
s22,s23,s24,s25,s26,s27,s28,s29,s30,s31,s32,s33,s34,s35,s36,s37,s38,s39,s40, 
s41,s42,s43,s44,s45,s46,s47,s48,s49,s50,s51,s52,s53,s54,s55,s56,s57,s58 = split.unpack(s) 
3

要分割字符串,使用gmatch:

local my_string = [[12-05-17 12:48:48 12.3 23 -8.2 1 2 225 0.0 0.0 992.3 SW 1 m/s C hPa mm 49.8 +0.1 0.6 60.0 0.0 21.5 31 12.3 +0.7 13.0 11:31 1.2 01:31 4 10:40 7 09:36 992.4 12:28 989.4 00:00 1.9.4 1099 6 12.3 12.3 0 0.00 0 176 0.0 24 1 0 S 2560 m 8.7 0.0 750 0 ]] 

local vars= {} 
for word in my_string:gmatch('(.-)[%s]+') do 
    vars[#vars+1] = word 
     print(#vars,word) 
end 
local Date = vars[1] 
local Time = vars[2] 
local Temp = vars[3] 
-- and etc. 

(長字符串可以用方括號[[]]括起來)

+0

「長字符串」用什麼意思括在方括號[[]]中?這與問題有什麼關係? – nobody

+0

@沒人好,那我可能就過頭了,糾正我的回答 –

5

我想你會使用數組會更好:

data = "12-05-17 12:48:48 12.3 23 -8.2 1 2 225 0.0 0.0 992.3 SW 1 m/s C hPa mm 49.8 +0.1 0.6 60.0 0.0 21.5 31 12.3 +0.7 13.0 11:31 1.2 01:31 4 10:40 7 09:36 992.4 12:28 989.4 00:00 1.9.4 1099 6 12.3 12.3 0 0.00 0 176 0.0 24 1 0 S 2560 m 8.7 0.0 750 0 " 

value = { } 
n = 0 

for v in data:gmatch("%S+") do 
    n = n + 1 
    value[n]=v 
end 

Date = value[1] 
Time = value[2] 
Temp = value[3] 
Humidity = value[4] 
WindSpeed = value[13] 
HighTemp = value[27] 
CloudBase = value[53] 

print(Date,Time,Temp,Humidity,WindSpeed,HighTemp,CloudBase)