類型不匹配插入：帶有Ecto變更集的binary_id

Question

我有一個表applications，其中包含一個外鍵user_id，這是一個Postgres uuid。我有我的web.ex：

@primary_key {:id, :binary_id, autogenerate: true} 
    @foreign_key_type :binary_id 

我的模式是：

defmodule Dashboard.Application do 
    use Dashboard.Web, :model 

    alias Dashboard.User 
    alias Dashboard.Path 

    schema "applications" do 
    field :name, :string 
    belongs_to :user, User 
    has_many :paths, Path 
    timestamps 
    end 

    @required_fields ~w(name user_id) 
    @optional_fields ~w() 

    def changeset(model, params \\ :empty) do 
    model 
    |> cast(params, @required_fields, @optional_fields) 
    end 
end 

但是當我嘗試使用有效的UUID從我users表做了變更插入，我越來越

[error] #PID<0.407.0> running Dashboard.Endpoint terminated 
Server: localhost:4000 (http) 
Request: POST /applications 
** (exit) an exception was raised: 
    ** (Ecto.ChangeError) value `<<184, 235, 134, 244, 95, 86, 74, 133, 159, 153, 31, 111, 16, 28, 76, 15>>` for `Dashboard.Application.user_id` in `insert` does not match type :binary_id 
     (ecto) lib/ecto/query/planner.ex:33: anonymous fn/6 in Ecto.Query.Planner.fields/4 
     (stdlib) lists.erl:1262: :lists.foldl/3 
     (ecto) lib/ecto/query/planner.ex:21: Ecto.Query.Planner.fields/4 
     (ecto) lib/ecto/repo/schema.ex:449: Ecto.Repo.Schema.dump_changes/5 
     (ecto) lib/ecto/repo/schema.ex:77: anonymous fn/11 in Ecto.Repo.Schema.do_insert/4 
     (ecto) lib/ecto/repo/schema.ex:477: anonymous fn/3 in Ecto.Repo.Schema.wrap_in_transaction/9 
     (ecto) lib/ecto/pool.ex:292: Ecto.Pool.with_rollback/3 
     (ecto) lib/ecto/adapters/sql.ex:582: Ecto.Adapters.SQL.transaction/8 
     (ecto) lib/ecto/pool.ex:244: Ecto.Pool.outer_transaction/6 
     (ecto) lib/ecto/adapters/sql.ex:551: Ecto.Adapters.SQL.transaction/3 
     (dashboard) web/controllers/application_controller.ex:16: Dashboard.ApplicationController.create/2 

檢查user_id我看到：

pry(1)> params["user_id"] |> i 
Term 
    <<184, 235, 134, 244, 95, 86, 74, 133, 159, 153, 31, 111, 16, 28, 76, 15>> 
Data type 
    BitString 
Byte size 
    16 
Description 
    This is a binary: a collection of bytes. It's printed with the `<<>>` 
    syntax (as opposed to double quotes) because it is not a 
    UTF-8 encoded binary (the first invalid byte being `<<184>>`) 
Reference modules 
    :binary 

這看起來像是試圖向我插入一個有效的16字節uuid。我錯過了什麼？謝謝！

更新：這是DB模式：

   Table "public.applications" 
    Column |   Type    | Modifiers 
-------------+-----------------------------+----------- 
id   | uuid      | not null 
user_id  | uuid      | not null 
name  | text      | not null 
inserted_at | timestamp without time zone | not null 
updated_at | timestamp without time zone | not null 
Indexes: 
    "applications_pkey" PRIMARY KEY, btree (id) 
    "applications_user_id_index" btree (user_id) 
Foreign-key constraints: 
    "applications_user_id_fkey" FOREIGN KEY (user_id) REFERENCES users(id) ON DELETE CASCADE 
Referenced by: 
    TABLE "paths" CONSTRAINT "paths_application_id_fkey" FOREIGN KEY (application_id) REFERENCES applications(id) ON DELETE CASCADE 

       Table "public.users" 
    Column |   Type    | Modifiers 
-------------+-----------------------------+----------- 
id   | uuid      | not null 
email  | text      | not null 
inserted_at | timestamp without time zone | not null 
updated_at | timestamp without time zone | not null 
avatar  | text      | not null 
name  | text      | not null 
data  | jsonb      | not null 
Indexes: 
    "users_pkey" PRIMARY KEY, btree (id) 
    "users_email_index" UNIQUE, btree (email) 
Referenced by: 
    TABLE "applications" CONSTRAINT "applications_user_id_fkey" FOREIGN KEY (user_id) REFERENCES users(id) ON DELETE CASCADE 

更新2： 我已經升級到1.2鳳和外生2.0.2和問題仍然存在

更新3： 我覺得這可能是Ecto中的一個錯誤。我開了一家公關與修復我的最好的嘗試：https://github.com/elixir-ecto/ecto/pull/1585

Answer 1

外生架構使用binary_id期望數據爲字串格式化UUID，然後由外生自動轉換爲16字節的二進制格式。

如果你想直接用二進制表示的工作，您可以定義類型爲:binary

schema "applications" do 
    field :name, :string 
    belongs_to :user, User, foreign_key: :user_id, type: :binary 
    has_many :paths, Path 
    timestamps 
end 

或者二進制數據轉換成字符串Ecto.UUID.load：

iex(38)> binary = Ecto.UUID.bingenerate() 
<<91, 154, 58, 233, 38, 235, 76, 200, 188, 162, 112, 23, 233, 223, 191, 144>> 
iex(39)> Ecto.UUID.load(binary) 
{:ok, "5b9a3ae9-26eb-4cc8-bca2-7017e9dfbf90"} 

Answer 2

檢查您的遷移文件，並確保您要爲id字段正確的數據類型。

add :user_id, references(:users, type: :uuid)