如何在iPhone的NSString中獲取並獲取URL？

Question

我在http：//在NSString中有一個文本。我想從NSString獲取該鏈接。我怎麼能從字符串中獲得鏈接/網址？例如：'疊加流程對於初學者https://stackoverflow.com/'非常有用。我想從文本中獲得'https://stackoverflow.com/'。我怎樣才能做到這一點？提前致謝。

Answer 1

我不知道你到底是通過鏈接的意思，但如果你想你的NSString轉換爲NSURL比你可以做到以下幾點：

NSString *urlString = @"http://somepage.com"; 
NSURL *url = [NSURL URLWithString:urlString]; 

編輯

這是怎麼弄在給定的NSString所有網址：

NSString *str = @"This is a grate website http://xxx.xxx/xxx you must check it out"; 

NSArray *arrString = [str componentsSeparatedByString:@" "]; 

for(int i=0; i<arrString.count;i++){ 
    if([[arrString objectAtIndex:i] rangeOfString:@"http://"].location != NSNotFound) 
     NSLog(@"%@", [arrString objectAtIndex:i]); 
} 

Answer 2

試試這個：

nsstring *str = @"Stack over flow is very useful link for the beginners http://stackoverflow.com/"; 

nsstring *http = @"http"; 
nsarray *arrURL = [str componentsSeparatedByString:@"http"]; 

這會在nsarray中給出兩個對象。第一個對象將是具有：Stack over flow is very useful link for the beginners和2將是：://stackoverflow.com/（我猜）

，那麼你可以這樣做：

NSString *u = [arrURL lastObject]; 

那麼就喜歡：

nsstring *http = [http stringByAppendingFormat:@"%@",u]; 

相當漫長的，但我認爲這會對你有用。希望能幫助你。

Answer 3

而不是分裂的字符串到一個數組，折騰了這種方式，你可以搜索字符串以@開頭的「http：//」：

NSString *str = @"Stack over flow is very useful link for the beginners http://stackoverflow.com/"; 
// get the range of the substring starting with @"http://" 
NSRange rng = [str rangeOfString:@"http://" options:NSCaseInsensitiveSearch]; 

// Set up the NSURL variable to hold the created URL 
NSURL *newURL = nil; 

// Make sure that we actually have found the substring 
if (rng.location == NSNotFound) { 
    NSLog(@"URL not found"); 
    // newURL is initialised to nil already so nothing more to do. 
} else { 
    // Get the substring from the start of the found substring to the end. 
    NSString *urlString = [str substringFromIndex:rng.location]; 

    // Turn the string into an URL and put it into the declared variable 
    newURL = [NSURL URLWithString:urlString]; 
}