我如何解決weekofyear（'20121231'）返回1？

Question

weekofyear('20121231')返回1，而weekofyear('20121230')收益52

Mysql Ver 5,1,47 Cummunity Nt/Windows 7 32 Bit/ODBC 5.1.10/
First day of Week : Sunday 

它應該返回53，但其返回1， week('20121231',1)，week('20121230')回53在這兩種情況下

Answer 1

week需要大量的參數，weekofyear只是一個這些表格與week([date], 3)相同。

閱讀manual查看不同的選擇。

SQLFiddle

Answer 2

按照documentation，weekofyear('20121231')是不相當於week('20121231',1)：

WEEKOFYEAR()是相當於 WEEK(date,3)兼容性功能。

測試它：

mysql> SELECT weekofyear('20121231'), week('20121231',1), week('20121231',3); 
+------------------------+--------------------+--------------------+ 
| weekofyear('20121231') | week('20121231',1) | week('20121231',3) | 
+------------------------+--------------------+--------------------+ 
|      1 |     53 |     1 | 
+------------------------+--------------------+--------------------+