1
我想根據會話數量從MySQL數據庫中多次取回項目。根據會話結果數量回顯項目
例子:
id | qty | item
1 | 2 | shoe
2 | 4 | net
3 | 3 | phone
我的結果集應該是這樣的:
shoe, shoe
net, net, net, net
phone, phone, phone
我想:
if(isset($_SESSION["cart_products"]))
foreach ($_SESSION["cart_products"] as $each_item){
$item_id = $each_item['item_id'];
$qty = $each_item['quantity'];
$sql = mysql_query("SELECT * FROM products WHERE id='$item_id' ORDER BY id");
$qty = array();
while ($row = mysql_fetch_array($sql)) {
$qty[] = $row;
}foreach($qty as $row){
$product_name = $row["product_name"];
}
echo'$product_name';
任何幫助表示讚賞。
$ qty是一個會話結果而不是數據庫結果,它在數據庫中沒有culumn它應該這樣嗎? <?php session_start(); 包含「mysql.php」;如果(!isset($ _ SESSION [「cart_array」])|| count($ _ SESSION [「cart_array」])<1) ?> <?php echo「shopping is empty」; } else foreach($ _ SESSION [「cart_array」] as $ each_item){ $ item_id = $ each_item ['item_id']; $ qty = $ each_item ['quantity']; $ sql = mysql_query(「SELECT * FROM products WHERE id ='$ item_id' ORDER BY id」); while($ row = mysql_fetch_array($ sql)){ for($ i = 0; $ i <$ qty; $ i ++){ $ y = $ row ['product_name']; } echo'$ y'; } } } ?> –