它不使用webrequest發送文本到網站

Question

我想以編程方式將數據發送到網站，然後以編程方式單擊提交按鈕。這是HTML代碼我試圖填補：

<textarea id="rpslBox:postRpsl:rpslObject" name="rpslBox:postRpsl:rpslObject" class="ripe-input-field ui-corner-all" rows="18" style="width:500px;"></textarea> 

我使用此C＃代碼：

WebRequest request = WebRequest.Create("https://apps.db.ripe.net/syncupdates/simple-rpsl.html "); 
// Set the Method property of the request to POST. 
request.Method = "POST"; 
string textarea = "text"; 

// Create POST data and convert it to a byte array. 
string postData = string.Format("rpslBox:postRpsl:rpslObject{0}", textarea); 

當我運行此代碼返回頁面的HTML代碼，而不發送本文。我怎樣才能發送這個文本？謝謝你的幫助！

Answer 1

我無法測試，如果這個工程，但是從我的理解msdn是，下面的代碼將在您的POSTDATA轉換爲bytedata並提交到Web服務器：

byte[] byteArray = Encoding.UTF8.GetBytes (postData); 
// Set the ContentType property of the WebRequest. 
request.ContentType = "application/x-www-form-urlencoded"; 
// Set the ContentLength property of the WebRequest. 
request.ContentLength = byteArray.Length; 
// Get the request stream. 
Stream dataStream = request.GetRequestStream(); 
// Write the data to the request stream. 
dataStream.Write (byteArray, 0, byteArray.Length); 
// Close the Stream object. 
dataStream.Close(); 

這事後下面的代碼可用於讀取來自Web服務器的新的響應：

// Get the response. 
WebResponse response = request.GetResponse(); 
// Display the status. 
Console.WriteLine (((HttpWebResponse)response).StatusDescription); 
// Get the stream containing content returned by the server. 
dataStream = response.GetResponseStream(); 
// Open the stream using a StreamReader for easy access. 
StreamReader reader = new StreamReader (dataStream); 
// Read the content. 
string responseFromServer = reader.ReadToEnd(); 
// Display the content. 
Console.WriteLine (responseFromServer); 
// Clean up the streams. 
reader.Close(); 
dataStream.Close(); 
response.Close();