腓循環throught XML節點

Question

我對XML文件中像

<response> 
<tag1> 
    <item> 
     <id>106</id> 
     <title>DG</title> 
    </item> 
    <item> 
     <id>105</id> 
     <title>AC</title> 
    </item> 
</tag1> 
<tag2> 
    <item> 
     <id>1</id> 
     <title>DjG</title> 
    </item> 
    <item> 
     <id>15</id> 
     <title>AoC</title> 
    </item> 
</tag2> 
</response> 

我想這個代碼以提取ID和標題

$dom = new DomDocument(); 
    $dom->load('xml.xml'); 
    $xpath = new DOMXPath($dom); 

    foreach($xpath->evaluate('//response/*') as $node){ 
    $params =$xpath->evaluate('//response/' .$node->nodeName . '/item/*'); 
     foreach($params as $child) { 
      echo $node->nodeName ." = " .$child->nodeName ." = " .$child->nodeValue ."\n<br>"; 
     } 
    } 

，但我得到的結果，例如

<br>tag1 = id = 106 
<br>tag1 = title = DG 
<br>tag1 = id = 105 
<br>tag1 = title = AC 
<br>tag2 = id = 1 
<br>tag2 = title = DjG 
<br>tag2 = id = 15 
<br>tag2 = title = AoC 

但我需要像這樣得到

TAG1 = 106 = DG
TAG1 = 105 = AC
TAG2 = 1 = DJG
TAG2 = 15 = AoC的

Answer 1

在第二foreach ，只是目標$node->nodeName，然後在內部的foreach目標每個id一個標題。

foreach($xpath->evaluate('//response/*') as $node) { 
    $tag = $node->nodeName; 
    $params = $xpath->evaluate("//$tag/*"); 
    foreach($params as $child) { 
     $id = $xpath->evaluate('string(./id)', $child); 
     $title = $xpath->evaluate('string(./title)', $child); 
     echo $tag ." = " .$id ." = " .$title ."\n<br>"; 
    } 
} 

Sample Output

還是SimpleXML版本：

$xml = simplexml_load_file('xml.xml'); 
foreach($xml as $tag =>$node) { 
    foreach($node as $item => $child) { 
     echo $tag ." = " .$child->id ." = " .$child->title ."\n<br>"; 
    } 
} 

Sample Output

Answer 2

使用此代碼：

$dom = new DomDocument(); 
$dom->load('xml.xml'); 
$xpath = new DOMXPath($dom); 
foreach($xpath->evaluate('//response/*') as $node){ 
    $params =$xpath->evaluate('//response/' .$node->nodeName . '/*'); 

    foreach($params as $child) 
    { 
     echo $node->nodeName ." = " .$child->getElementsByTagName('id')->item(0)->textContent ." = " .$child->getElementsByTagName('title')->item(0)->textContent ."\n<br>"; 
    } 
} 

Answer 3

DOMXpath的第二個參數::評估（）是上下文節點。如果你不用斜槓啓動XPath表達式，它將與它相關。因此，在一個循環中，您通常希望將當前節點用作表達式的上下文。

foreach ($xpath->evaluate('/absolute-expression') as $node) { 
    var_dump(
    $xpath->evaluate('relative-expression', $node) 
); 
} 

XPath（與CSS選擇器不同）可以獲取沿不同軸的元素屬性。你可以得到當地名（不帶命名空間前綴）父節點：

local-name(parent::*)

利用這一點，你可以用一個循環遍歷item元素解決問題。

實施例：

$dom = new DomDocument(); 
$dom->loadXml($xml); 
$xpath = new DOMXPath($dom); 

foreach ($xpath->evaluate('//response/*/item') as $node) { 
    echo 
    $xpath->evaluate('local-name(parent::*)', $node), ' = ', 
    $xpath->evaluate('string(id)', $node), ' = ', 
    $xpath->evaluate('string(title)', $node), "\n"; 
} 

輸出：

tag1 = 106 = DG 
tag1 = 105 = AC 
tag2 = 1 = DjG 
tag2 = 15 = AoC 

只是，如果需要調用源的每個第一級節點（TAG1，TAG2）。你將需要兩個循環。像輸出由標籤*元素節點分組的項目一樣。

$dom = new DomDocument(); 
$dom->loadXml($xml); 
$xpath = new DOMXPath($dom); 

foreach ($xpath->evaluate('//response/*') as $node) { 
    echo 
    $xpath->evaluate('local-name()', $node), 
    "\n--------\n"; 
    foreach ($xpath->evaluate('item', $node) as $item) { 
    echo 
     $xpath->evaluate('string(id)', $item), ' = ', 
     $xpath->evaluate('string(title)', $item), "\n"; 
    } 
    echo "\n"; 
} 

輸出：

tag1 
-------- 
106 = DG 
105 = AC 

tag2 
-------- 
1 = DjG 
15 = AoC