我對發現錯誤感到厭倦。我沒有發現任何錯誤,但我沒有從editText獲取文本。請看下面的代碼:對話框上的EditText沒有返回任何文字
activity_pwd.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/layout_root"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="vertical"
android:padding="10dp" >
<TextView
android:id="@+id/textView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Enter PIN "
android:textAppearance="?android:attr/textAppearanceLarge" />
<EditText
android:id="@+id/pwdValue"
android:layout_width="match_parent"
android:maxLength="4"
android:maxLines="1"
android:inputType="numberPassword"
android:layout_height="wrap_content">
</EditText>
</LinearLayout>
我叫LockImmediately(本);上方法的onCreate MainActivity
public void LockImmediately(Context context) {
if (lock_app) {
View myview = LayoutInflater.from(context).inflate(R.layout.activity_pwd,null);
enterPWD = (EditText) myview.findViewById(R.id.pwdValue);
AlertDialog alertDialog = new AlertDialog.Builder(this).setCancelable(false)
.setView(R.layout.activity_pwd).setPositiveButton("OK", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
String user_text = enterPWD.getText().toString();
Log.d("onCreate pws", " i "+user_text);
if (pwd.equals(user_text)) {
dialog.dismiss();
Log.d("onCreate", "Work done");
} else {
dialog.dismiss();
MainActivity.this.finish();
}
}
}).create();
alertDialog.show();
}
}
Log.d
02-15 23:15:30.840 29379-29379/com.developersqueen.wishlater D/onCreate: onCreate
02-15 23:15:37.021 29379-29379/com.developersqueen.wishlater D/onCreate pws: i
02-15 23:15:45.427 29379-29379/com.developersqueen.wishlater D/onCreate: onCreate
02-15 23:15:49.026 29379-29379/com.developersqueen.wishlater D/onCreate pws: i
你可以看到上面那個日誌我有 「我」,但它沒有返回值連接的EditText值..我已經嘗試清除數據,unistalling應用程序,乾淨,建立一切,但總是相同的結果!任何幫助,將不勝感激..
嘗試更改'enterPWD.getText()。toString();'alertDialog.findViewById(R.id.pwdValue).getText()。toString();',看它是否有效 – Sanjeet
不,它給出錯誤對編譯非法字符\ u200c –
然後刪除那個非法字符並試試 – Sanjeet