我試圖構建一個示例應用程序,它從url獲取一些json並將其顯示在表視圖中。我有一個問題,將數據存儲到一個對象中,並將這些對象插入到NSMutableArray中。將對象存儲到NSMutableArray中
TableView.m
- (void) getDataFromAPI {
NSString *endpoint = @"http://www.somesite.com/list.php";
NSURL *url = [NSURL URLWithString:endpoint];
NSURLRequest *request = [NSURLRequest requestWithURL:url];
AFJSONRequestOperation *operation = [AFJSONRequestOperation JSONRequestOperationWithRequest:request success:^(NSURLRequest *request, NSHTTPURLResponse *response, id JSON) {
[self createMovies: JSON];
} failure:^(NSURLRequest *request, NSHTTPURLResponse *response , NSError *error , id JSON){
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Alert" message:@"Uh oh, there's been a problem!" delegate:nil cancelButtonTitle:@"Cancel" otherButtonTitles:@"Retry", nil];
[alert show];
}];
[operation start];
}
- (void) createMovies: (id) json {
NSMutableArray *list = [[NSMutableArray alloc] init];
for (id entry in json) {
Movie *aMovie = [[Movie alloc] init];
aMovie.movieId = [entry objectForKey:@"id"];
aMovie.title = [entry objectForKey:@"title"];
aMovie.director = [entry objectForKey:@"director"];
aMovie.price = [entry objectForKey:@"price"];
aMovie = nil;
}
NSLog(@"%@", list);
self.movieList = list;
}
- (void)viewDidLoad
{
self.movieList = [[NSMutableArray alloc] init];
[super viewDidLoad];
[self getDataFromAPI];
self.title = @"Movies";
NSLog(@"%@", self.movieList);
}
當我嘗試檢查self.movieList
在viewDidLoad
它具有零個對象,但是當我在createMovies
檢查list
我得到六個對象。
的json數據的例子:
[
{
"id": 1,
"title": "Transformers",
"price": 29.54,
"Director": "Michael Bay"
},
{
"id": 2,
"title": "South Park",
"price": 34.88,
"author": "Matt Stone, Trey Parker"
},
{
"id": 3,
"title": "The Hobbit",
"price": 20.04,
"author": "Peter Jackson"
}
]
那麼,你的請求是異步的... –