是否有Python 2的等效Javascripts confirm（）命令？

短版本就是問題。是否有Python 2的等效Javascripts confirm（）命令？

較長版本：我通過Codecademy學習Javascript，同時嘗試重新學習Python 2。我剛剛完成了「選擇你自己的冒險故事」。

在下面的代碼，我可以找出如何輕鬆地在2號線

// Check if the user is ready to play! 
confirm("It's gametime!"); 
var age = prompt("What's your age"); 
if (age < 13) 
{ 
console.log("You're really young, but go play"); 
} 
else 
{ 
    console.log("You're old enough. Start playing"); 
} 
console.log("You are at a Justin Bieber concert, and you hear this lyric 'Lace my shoes off, start racing.'"); 
console.log("Suddenly, Bieber stops and says, 'Who wants to race me?'"); 
var userAnswer = prompt("Do you want to race Bieber on stage?"); 
if (userAnswer === "yes") 
{ 
    console.log("You and Bieber start racing. It's neck and neck! You win by a shoelace!"); 
} 
else 
{ 
    console.log("Oh no! Bieber shakes his head and sings 'I set a pace, so I can race without pacing.'"); 
} 
var feedback = prompt("Rate this game from 1-10"); 
if (feedback > 8) 
{ 
    console.log("Thank you! We should race at the next concert!"); 
} 
else 
{ 
    console.log("I'll keep practicing coding and racing."); 
}

調整一切到Python 2除了代碼除確認命令我會很感激的任何幫助。非常感謝。

來源

2015-04-25 MattGoldwater

你爲什麼要無視'確認（）的返回值'打電話？如果你不能取消，爲什麼要使用它？ Python沒有這樣的對話框，你可以創建一個函數，要求輸入'yes'或'no'，參見[詢問用戶輸入，直到他們給出有效響應]（http://stackoverflow.com/q/23294658）尋求這些功能的幫助。 –

如果你想要一個GUI對話框，你可以使用'tkinter'的'askyesno（）'函數。 – TigerhawkT3

如果你試圖在命令行中從用戶捕獲輸入您將使用raw_input功能：

age = raw_input("What's your age?\n")

來源

2015-04-25 17:36:14 Jesse

是否有Python 2的等效Javascripts confirm（）命令？

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