Android的XML解析代碼使用kxml.zip

Question

am使用此代碼來解析xml文件我有url地址，但它給了我的錯誤android os網絡主線程異常在這句話 URLConnection httpConnection = url.openConnection（ ）;inputStream = httpConnection.getInputStream（）; 這是我的代碼：

package com.example.mainp; 

import java.io.IOException; 
import java.io.InputStream; 
import java.io.InputStreamReader; 
import java.net.URL; 
import java.net.URLConnection; 
import java.util.Vector; 

import org.apache.http.HttpConnection; 
import org.kxml.Xml; 
import org.kxml.parser.XmlParser; 
import org.kxml.parser.ParseEvent; 
import org.kxml.parser.XmlParser; 

import android.app.Activity; 
import android.widget.Toast; 






public class parse { 

    public static Vector places; 
    Activity ac; 
    Place place; 
     private ParseEvent event = null; 
    public void init(Activity activity) { 
     this.ac=activity; 
     XmlParser parser = null; 
     InputStreamReader isR = null; 
     HttpConnection connection = null; 
     try { 

      InputStream inputStream = null; 
      System.out.println("0"); 
      Toast.makeText(ac, "24", Toast.LENGTH_LONG).show(); 
      //URL url = new URL("http://217.52.114.3/Mobinil%20Islamic%20WebService/MobinilIslamicService.asmx/GetIslamicDirectory"); 
      URL url= new URL("http://217.52.114.3/CinemaGuid/CinemaGuid.asmx/getTVSchedule"); 
      System.err.println("2"); 
      URLConnection httpConnection = url.openConnection(); 
      inputStream = httpConnection.getInputStream(); 
//   inputStream = connection.openInputStream(); 
      Toast.makeText(ac, "4", Toast.LENGTH_LONG).show(); 
      isR = new InputStreamReader(inputStream, "UTF-8"); 
      System.out.println("3"); 
      parser = new XmlParser(isR); 
      System.out.println("4"); 
      Toast.makeText(activity, "5", Toast.LENGTH_LONG).show();  
      places = new Vector<Place>(); 
      traverse(parser); 
      isR.close(); 
      inputStream.close(); 
      inputStream = null; 
      isR = null; 
      // System.gc(); 
     } catch (Exception ex) { 
      Toast.makeText(activity, ex.toString(), Toast.LENGTH_LONG).show(); 
     } 
    } 
    private void traverse(XmlParser parser) { 
     // TODO Auto-generated method stub 
     boolean leave = false; 
     do { 
      try { 
       event = parser.read(); 
       ParseEvent pe; 
       switch (event.getType()) { 
        case Xml.START_TAG: 
         // see API doc of StartTag for more access methods 
         // Pick up Title for display 
         if("places".equalsIgnoreCase(event.getName())){ 
          places = new Vector(); 
          //Toast.makeText(ac, "6", Toast.LENGTH_LONG).show();  
         } 
         if("places".equalsIgnoreCase(event.getName())){ 
          place = new Place(); 
          place.setName(event.getValue("name")); 
          place.seturl(event.getValue("url")); 
          place.setaddress(event.getValue("adress")); 
          //Toast.makeText(MainPActivity.this, "7", Toast.LENGTH_LONG).show();  

         } 
         if("description".equalsIgnoreCase(event.getName())){ 
          pe = parser.read(); 
          if(pe.getText()!=null){ 
           place.setdescription(pe.getText().toString()); 
          } 
         } 
         traverse(parser); // recursion call for each <tag></tag> 
         break; 
        case Xml.END_TAG: 
         if ("Place".equalsIgnoreCase(event.getName())) { 
          places.addElement(place); 
         // Toast.makeText(MainPActivity.this, "8", Toast.LENGTH_LONG).show(); 
         } 
         leave = true; 
         break; 
        case Xml.END_DOCUMENT: 
         leave = true; 
         break; 
        case Xml.TEXT: 
         break; 
        case Xml.WHITESPACE: 
         break; 
        default: 
       } 
      } catch (Exception ex) { 
       Toast.makeText(ac, ex.getMessage(), Toast.LENGTH_LONG).show(); 

      } 
     } while (!leave); 

    } 
} 

Answer 1

任何網絡調用都應該在一個單獨的線程中完成。您正在UI（默認）主線程中進行網絡調用，並且Android 4.0+在此上引發異常。考慮的AsyncTask或工作線程有你的長時間運行的任務在另一個進程

http://developer.android.com/guide/components/processes-and-threads.html