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我的表Tour有兩個相關的字段用戶表user_id(遊覽所有者)和modified_by(誰最後修改了它) 問題是我不知道如何與他們建立關係。 如果我寫:在yii 1.1.x中設置關係如果表關聯兩次
public function relations()
{
return array(
'belongs_to_modified_by_user' => array(self::BELONGS_TO, 'User', 'modified_by'),
'belongs_to_user_id_user' => array(self::BELONGS_TO, 'User', 'user_id'),
)
}
我得到錯誤:
Syntax error or access violation: 1066 Not unique table/alias: 'user'
如何正確?
我特林讓它,但它失敗:
public function relations()
{
return array(
'belongs_to_modified_by_user' => array(self::BELONGS_TO, 'User', 'modified_by', 'alias' => 'modi'),
'belongs_to_user_id_user' => array(self::BELONGS_TO, 'User', 'user_id', 'alias' => 'touser'),
'belongs_to_category' => array(self::BELONGS_TO, 'Category', 'category_id'),
'belongs_to_region' => array(self::BELONGS_TO, 'Region', 'region_id'),
'belongs_to_subregion' => array(self::BELONGS_TO, 'Subregion', 'subregion_id'),
'belongs_to_state' => array(self::BELONGS_TO, 'State', 'state_id'),
);
}
...
In method for data retrieving:
$criteria = new CDbCriteria;
$criteria->alias = 'T';
$criteria->with[] = 'belongs_to_modified_by_user';
$criteria->with[] = 'belongs_to_user_id_user';
$criteria->with[] = 'belongs_to_category';
$criteria->with[] = 'belongs_to_region';
$criteria->with[] = 'belongs_to_subregion';
$criteria->with[] = 'belongs_to_state';
But I get error :
CDbCommand failed to execute the SQL statement: SQLSTATE[42000]: Syntax error or access violation: 1066 Not unique table/alias: 'user'. The SQL statement executed was: SELECT COUNT(DISTINCT `T`.`id`) FROM `tyb_tour` `T` LEFT JOIN tyb_category as c ON c.id = T.category_id LEFT OUTER JOIN `tbl_users` `user` ON (`T`.`modified_by`=`user`.`id`) LEFT OUTER JOIN `tbl_profiles` `profile` ON (`profile`.`user_id`=`user`.`id`) LEFT OUTER JOIN `tbl_users` `user` ON (`T`.`user_id`=`user`.`id`) LEFT OUTER JOIN `tbl_profiles` `profile` ON (`profile`.`user_id`=`user`.`id`) LEFT OUTER JOIN `tyb_category` `belongs_to_category` ON (`T`.`category_id`=`belongs_to_category`.`id`) LEFT OUTER JOIN `tyb_region` `belongs_to_region` ON (`T`.`region_id`=`belongs_to_region`.`id`) LEFT OUTER JOIN `tyb_subregion` `belongs_to_subregion` ON (`T`.`subregion_id`=`belongs_to_subregion`.`id`) LEFT OUTER JOIN `tyb_state` `belongs_to_state` ON (`T`.`state_id`=`belongs_to_state`.`id`) WHERE (T.user_id=:ycp0). Bound with :ycp0='2'
如果我的別名格式是否正確?
你的代碼是正確的,這個錯誤是不相關的這些關係可言,請嘗試跟蹤您的代碼,並確切地知道行拋出這個錯誤 –