蟒蛇ONELINE創建的給定的順序

Question

我找蟒蛇矩陣oneliner將創建矩陣給定的順序，從1填充值到n。 N = [R XÇ

我實現這個錢櫃，

Matrix1 = [[x+1 for x in range(rowCount)] for x in range(columnCount)] 
print Matrix1 

但輸出

[[1, 2, 3], [1, 2, 3], [1, 2, 3]] 

Answer 1

>>> matrix1 = [[1+x+y*rowCount for x in range(rowCount)] for y in range(columnCount)] 
>>> matrix1 
[[1, 2, 3], [4, 5, 6], [7, 8, 9]] 

Answer 2

可以使用相同的變量爲你的兩個循環。試試這個：

matrix1 = [[y*rowCount + x + 1 for x in range(rowCount)] for y in range(columnCount)] 
print matrix1 

Answer 3

不，正確的做法是沒有環路（在同一行）：

import numpy as np 

rowCount = 2 
colCount = 5 

np.array(range(1, 1+rowCount*colCount)).reshape(rowCount,colCount) 

#array([[ 1, 2, 3, 4, 5], 
#  [ 6, 7, 8, 9, 10]]) 

Answer 4

鑑於c（列數），n，這裏就是我想出了：

[range(0, n)[cx:cx+c] for cx in range(0, n, c)] 

結果：

In [16]: n = 9 

In [17]: c = 3 

In [18]: [range(0, n)[cx:cx+c] for cx in range(0, n, c)] 
Out[18]: [[0, 1, 2], [3, 4, 5], [6, 7, 8]] 

編輯：對於非方陣更多的例子： （mod是我創建迅速改變r和c價值，並從中計算n功能）

In [23]: mod(8, 2) # 8 rows, 2 columns 

In [24]: [range(0, n)[cx:cx+c] for cx in range(0, n, c)] 
Out[24]: [[0, 1], [2, 3], [4, 5], [6, 7], [8, 9], [10, 11], [12, 13], [14, 15]] 

In [25]: mod(3, 6) # 3 rows, 6 columns 

In [26]: [range(0, n)[cx:cx+c] for cx in range(0, n, c)] 
Out[26]: [[0, 1, 2, 3, 4, 5], [6, 7, 8, 9, 10, 11], [12, 13, 14, 15, 16, 17]] 

In [27]: mod(10, 3) # 10 rows, 3 columns 

In [28]: [range(0, n)[cx:cx+c] for cx in range(0, n, c)] 
Out[28]: 
[[0, 1, 2], 
[3, 4, 5], 
[6, 7, 8], 
[9, 10, 11], 
[12, 13, 14], 
[15, 16, 17], 
[18, 19, 20], 
[21, 22, 23], 
[24, 25, 26], 
[27, 28, 29]] 

它適用於他們。