PHP：如何從不同的數組中獲取公共值？

Question

我有兩個數組如下： -

$a = ["2","11","6"]; 
$b = ["6","7"]; 
$c = array_diff($a, $b); 

$c = ["2","11"]; 

結果在$c是錯誤的。我想要的結果應該是$c = [6]

換句話說我想在這兩個數組中的通用元素被返回！但它給錯誤的錯誤。請幫助我？

Answer 1

使用array_intersect()

$a = ["2","11","6"]; 
$b = ["6","7"]; 
$c = array_intersect($a, $b); 

演示：https://eval.in/682653

Answer 2

您可以使用array_intersect

$c = array_intersect($a, $b); 

Answer 3

$a = ["2","11","6"]; 
$b = ["6","7"]; 
$c = array_intersect($a,$b); 

Answer 4

使用array_intersect（http://php.net/manual/en/function.array-intersect.php）

<?php 
$a = ["2","11","6"]; 
$b = ["6","7"]; 
$c = array_intersect($a, $b); 

print_r($c) 

?>