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我在代碼後面動態創建了GridView。現在,在實際的DataBinding事件中,我已經有了一個保存編輯單元格及其值的JavaScript函數。這一切工作正常,沒有尋呼機,現在當我將尋呼機添加到GW我需要添加到JS功能的頁面索引,所以我可以計算後來哪個行/單元它實際上是被改變。無法將PageIndex添加到GridViewTemplate:ITemplate javascript函數
// Databind an edit box in the grid
void edt_DataBinding(object sender, EventArgs e)
{
DropDownList txtData = (DropDownList)sender;
GridViewRow container = (GridViewRow)txtData.NamingContainer;
object dataValue = DataBinder.Eval(container.DataItem, _columnName);
txtData.Attributes.Add("onchange", "sav(" + container.RowIndex.ToString() + "," + _columnName + ",this.value)");
if (dataValue != DBNull.Value)
{
txtData.SelectedItem.Text = dataValue.ToString();
txtData.BackColor = Color.LightGreen;
}
}
我嘗試添加「grdMain.PageIndex」的JS,但出現以下錯誤:「不能訪問外部類的非靜態成員....
txtData.Attributes.Add("onchange", "sav(" + grdMain.PageIndex + container.RowIndex.ToString() + "," + _columnName + ",this.value)");
任何智能的解決方法?
更多代碼:
public class GridViewTemplate : ITemplate
{
private ListItemType _templateType;
private string _columnName;
private string _col;
private string _dataType;
private bool _isLabel;
private bool _isCategory;
private string _types;
private IQueryable _role;
public GridViewTemplate(ListItemType type, string colname, string col, string DataType, bool isLabel, bool isCategory, string types, IQueryable role)
{
_templateType = type;
_columnName = colname;
_dataType = DataType;
_col = col;
_isLabel = isLabel;
_isCategory = isCategory;
_types = types;
_role = role;
}
void ITemplate.InstantiateIn(System.Web.UI.Control container)
{
Label lbl = new Label();
switch (_types)
{....
}
}
void lbl_DataBinding(object sender, EventArgs e)
{
Label lbl = (Label)sender;
GridViewRow container = (GridViewRow)lbl.NamingContainer;
object dataValue = DataBinder.Eval(container.DataItem, _columnName);
if (dataValue != DBNull.Value)
{
lbl.Text = dataValue.ToString();
}
}
// Databind an edit box in the grid
void edt_DataBinding(object sender, EventArgs e)
{....
}
}
按鈕點擊:
.....
TemplateField tfUsers = new TemplateField();
grdMain.Columns.Add(tfUsers);
tfUsers.ItemTemplate = new GridViewTemplate(ListItemType.Item, "Name", "0", "String", true, false, "resource", lame);
tfUsers.HeaderTemplate = new GridViewTemplate(ListItemType.Header, "Resource", "0", "String", true, false, "resource", lame);
_dtEntry.Columns.Add("Name");
......
是什麼grdMain?和你訪問的地方?看起來像page_load? – 2012-04-19 18:44:15
grdMain是GridView ID,並且我沒有在btn點擊創建表。 – Jake 2012-04-19 22:17:03