爲什麼我得到一個約束錯誤？

Question

我使用symfony的1.4，我的架構如下：

Auditor: 
    columns: 
    id: 
     type: integer 
     autoincrement: true 
     primary: true 
    username: 
     type: string(255) 
    password: 
     type: string(255) 
    fullname: 
     type: string(255) 
    is_auditor: 
     type: integer 
    is_manager: 
     type: integer 
    is_director: 
     type: integer 

Task: 
    columns: 
    id: 
     type: integer 
     autoincrement: true 
     primary: true 
    client: 
     type: string(255) 
    start_date: 
     type: date 
    end_date: 
     type: date 
    assigned_by: 
     type: string(255) 
    comments: 
     type: string 
    status: 
     type: integer 
    relations: 
    Auditors: 
     foreignAlias: Tasks 
     class: Auditor 
     refClass: AuditorTask 

AuditorTask: 
    columns: 
    id: 
     type: integer 
     autoincrement: true 
     primary: true 
    auditor_id: 
     type: integer 
     primary: true 
    task_id: 
     type: integer 
     primary: true 
    relations: 
    Auditor: 
     foreignAlias: AuditorTasks 
    Task: 
     foreignAlias: AuditorTasks 

Expense: 
    columns: 
    id: 
     type: integer 
     autoincrement: true 
     primary: true 
    auditor_task_id: 
     type: integer 
    date: 
     type: date 
    hours_spent: 
     type: integer 
    transport_cost: 
     type: float 
    remarks: 
     type: string 
    relations: 
    AuditorTask: 
     foreignAlias: Expenses 

當我嘗試創建一個新的任務，我得到以下錯誤：

SQLSTATE [HY000]：常規錯誤： 1452無法添加或更新子行，外鍵約束失敗

審計和任務有一個多對多的關係（ehrauditor_task，約束auditor_task_id_expense_auditor_task_id外鍵（id）參考文獻expense（auditor_task_id）。）臀部。從而結交表。審計師可以對任務發表意見，因此我使用審計任務和審計任務之間的一對多關係。

有什麼想法？

確定這裏是從調試的痕跡。

1 Info sfPatternRouting Match route "default" (/:module/:action/*) for /task/create with parameters array ('module' => 'task', 'action' => 'create',) 
2 Info sfFilterChain Executing filter "sfRenderingFilter" 
3 Info sfFilterChain Executing filter "sfExecutionFilter" 
4 Info taskActions Call "taskActions->executeCreate()" 
5 Info Doctrine_Connection_Mysql exec : SET NAMES 'UTF8' -() 
6 Info Doctrine_Connection_Statement execute : SELECT COUNT(*) AS num_results FROM auditor a WHERE a.id IN (?) - (1) 
7 Info Doctrine_Connection_Statement execute : SELECT a.id AS a__id, a.username AS a__username, a.password AS a__password, a.fullname AS a__fullname, a.is_auditor AS a__is_auditor, a.is_manager AS a__is_manager, a.is_director AS a__is_director FROM auditor a WHERE (a.id IN (?)) - (1) 
8 Info Doctrine_Connection_Statement execute : INSERT INTO task (client, start_date, end_date, assigned_by, comments, status) VALUES (?, ?, ?, ?, ?, ?) - (Falcon Limited, 2005-01-02, 2005-02-02, mr manager one, asap., 0) 
9 Info Doctrine_Connection_Statement execute : INSERT INTO auditor_task (auditor_id, task_id) VALUES (?, ?) - (1, 1) 
10 Error Doctrine_Connection_Mysql_Exception SQLSTATE[HY000]: General error: 1452 Cannot add or update a child row: a foreign key constraint fails (`ehr`.`auditor_task`, CONSTRAINT `auditor_task_id_expense_auditor_task_id` FOREIGN KEY (`id`) REFERENCES `expense` (`auditor_task_id`)) 
11 Info sfWebResponse Send status "HTTP/1.1 500 Internal Server Error" 
12 Info sfWebResponse Send header "Content-Type: text/html; charset=utf-8" 

Answer 1

看起來好像它是您在AuditorTask上定義的主鍵。您已將'id'，'auditor_id'和'task_id'設置爲PK。從「auditor_id」和「TASK_ID」及以下作品中刪除PK-聲明：

insert into auditor(username)values('user'); 
insert into task(client)values('The client'); 
insert into auditor_task(auditor_id, task_id)values(1,1); 
insert into expense(auditor_task_id, hours_spent)values(1,2); 

以供參考，這是AuditorTask的樣子修改後：

AuditorTask: 
    columns: 
    id: 
     type: integer 
     autoincrement: true 
     primary: true 
    auditor_id: 
     type: integer 
    task_id: 
     type: integer 
    relations: 
    Auditor: 
     foreignAlias: AuditorTasks 
    Task: 
     foreignAlias: AuditorTasks 

我看到你正在使用MySQL的。 MySQL是否甚至允許您按照他們定義的方式創建表？ Postgres（我主要使用）看到有些東西很腥，甚至不接受它定義的表格創建方式。 ;）