返回數組中的最小數字，而不使用數學運算

Question

我需要創建一個返回數組中最小數字的函數，我似乎無法弄清楚這個問題，因爲這裏的其他問題根本沒有幫助，因爲他們給出了我以前從未見過的代碼的答案，所以我有這個，但它總是隻返回「0」而不是80，那麼你能用我的代碼來幫助我嗎？

var value = [100, 90, 100, 80]; 
 

 
function lowestGrade(a) { 
 
    for (var i = 0; i < a.length; i++) { 
 
    if (a[i] < a.length); 
 
    value = i; { 
 
     return (value); 
 
    } 
 
    } 
 
} 
 

 
document.write(lowestGrade(value));

Answer 1

如已經提到的，有建於的方式來處理這個問題。但是，我認爲這是某種家庭作業問題。

var array = [90, 1, 77, -5, 101]; 
 

 
function lowest(arr) { 
 
    //Assume first is lowest 
 
    var low = arr[0]; 
 

 
    for (var i = 0; i < arr.length; i++) { 
 
    //If this isn't lower, swap 
 
    if (low > arr[i]) { 
 
     low = arr[i]; 
 
    } 
 
    } 
 

 
    //Will always contain lowest number 
 
    return low; 
 
} 
 

 
document.write(lowest(array));

Answer 2

的問題是在這裏;

function lowestGrade(a) { 
    for (var i = 0; i < a.length; i++) { 
    if (a[i] < a.length); // < -- this is an if statement which has no effect 
    value = i; // <-- this just set the value to the loop index i 
    { 
     return (value); // << -- this returns at the first loop where i is zeo 
    } 
    } 
} 

取而代之，

var value = [100, 90, 100, 80]; 
 
function lowestGrade(a) { 
 
    var lowest = a[0]; 
 
    for (var i = 0; i < a.length; i++) { 
 
    if (a[i] < lowest) 
 
     lowest = a[i]; 
 
    } 
 
    return lowest; 
 
} 
 

 
document.write(lowestGrade(value));

Answer 3

試試這個：

var value = [100, 90, 100, 80]; 
lowestGrade(value); 

function lowestGrade (value) 
{ 
    var lowest; 
    for(var i = 0, cnt = value.length; i<cnt; i++){ 
     if(typeof lowest === 'undefined') { 
      lowest = value[i] 
     } else { 
      if(value[i] < lowest){ 
       lowest = value[i]; 
      } 
     } 
    } 

    console.log(lowest); 
} 

小提琴here

Answer 4

既然你是專門要求在Javascript中不使用數學對象，有一個答案我已經在這裏找到在Stackoverflow中，以您想要的方式解決它：

function mymax(a) 
{ 
    var m = -Infinity, i = 0, n = a.length; 

    for (; i != n; ++i) { 
     if (a[i] > m) { 
      m = a[i]; 
     } 
    } 

    return m; 
} 

我並不擁有這個答案，所以請檢查這個鏈接，查看原單筆者的回答：https://stackoverflow.com/a/13794386/44852

Answer 5

var value = [100, 90, 100, 80]; 

function lowestGrade(a) { 
var lowestNum = a[0]; // Set it to first element 
    for (var i = 1; i < a.length; i++) { //loop through array, starting at first element if length is greater than 1 
    if (a[i] < lowestNum) 
     lowestNum = a[i]; //if the array value is lower than your variable, set your variable to it 
    } 
    return lowestNum; 
} 

document.write(lowestGrade(value)); 

Answer 6

如果你不學習如何進行排序，您可以使用本機reduce功能。

var value = [100, 90, 100, 80]; 
var min = value.reduce(function (pv,cv) { 
    return pv > cv?cv:pv 
}); 
document.write(min);