未定義的變量：第17行中的C：\ xampp \ htdocs \ training.php中的sql

-1

我試圖獲取該id並將其存儲在一個變量中，但它表明變量未定義，查詢是不是因爲變量而執行，我不明白爲什麼。未定義的變量：第17行中的C： xampp htdocs training.php中的sql

include 'connect.php'; 
    if(isset($_GET['OrgName'])) 
    { 
    $file=$_GET['OrgName']; 

$sql="SELECT oraganzation.OrgName,oraganzation.City,oraganzation.OrgEmail,oraganzation.OrgPhoneNO, oraganzation.Workfield, oraganzation.Trainingrecruitment, oraganzation.WebsiteLink,Student_comments.comment 
FROM oraganzation , Student_comments 
WHERE oraganzation.OrgName=$file AND oraganzation.OrgID=Student_comments.OrgID "; 
} 
$result= mysqli_query($con,$sql) or die ("could not found; ".mysqli_error ($con)); 

while ($row=mysqli_fetch_array($result)) 
{ 

    echo "<br><strong> Name : </strong>". $row['OrgName']. 
"<br><strong> 
<br><strong> City : </strong>". $row['City']. 
"<br><strong> 
Email: </strong>" . $row['OrgEmail']. 
"<br><strong> 
PhoneNO: </strong>". $row['OrgPhoneNO']. 
"<br> <strong> 
Work field: </strong> " . $row['Workfield']. 
"<br><strong> 
Training recruitment:</strong> " . $row['Trainingrecruitment']. 
"<br> <strong> 
Website Link: </strong> " . $row['WebsiteLink']. 
"<br> <strong> 
Comments: </strong> " .$row['comment']. "<br>" ; 

    }

這是從以前的頁面我的代碼，我把A HREF爲獲取名稱

$sql="SELECT OrgName, City, OrgEmail, OrgPhoneNO, Workfield, Trainingrecruitment, WebsiteLink,OrgID 
    FROM oraganzation"; 

$result= mysqli_query($con,$sql) or die ("could not found; ".mysqli_error($con)); 

while ($row=mysqli_fetch_array($result)) 
{ 

?> 

<div class="content "> 
<a href="training.php?name=<?php echo $row['OrgName'] ?> "><?php echo $row['OrgName'] ;?> </a> 

     <?php 
echo "<br><strong> City : </strong>". $row['City']. 
    "<br><strong> 
    Email: </strong>" . $row['OrgEmail']. 
    "<br><strong> 
    PhoneNO: </strong>". $row['OrgPhoneNO']. 
    "<br> <strong> 
    Work field: </strong> " . $row['Workfield']. 
"<br><strong> 
Training recruitment:</strong> " . $row['Trainingrecruitment']. 
    "<br> <strong> 
    Website Link: </strong> " . $row['WebsiteLink']. 


    "</div> ";} ?>

來源

2017-07-29 yara

$ SQL定義只有

if(isset($_GET['OrgName']))

你應該使封閉在運行查詢之後大括號$ sql，或者即使未設置OrgName，也可以定義$ sql

來源

2017-07-29 18:11:50 cornelb

未定義的變量：第17行中的C：\ xampp \ htdocs \ training.php中的sql

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