Bash if else聲明錯誤

Question

for ((c=0; c<$i; c++)); do 
if [[ "$aTitle" == "${bookTitle[$c]}" ]]; then 
if [[ "$aAuthor" == "${author[$c]}" ]]; then  
found=true 
fi 
fi 
done 

echo $found 

嗨，即時通訊相當新的shell編程，任何人都可以告訴我爲什麼我得到這個錯誤，當我運行這段代碼？非常感謝。 BOOKTITLE &作者是一個字符串數組 aTitle & aAuthor是輸入用戶

function add_new_book 
{ 
echo "1) add_new_book" 

found=false 

echo -n "Title: " 
read aTitle 
echo -n "Author: " 
read aAuthor 

for ((c=0; c<$i; c++)); do 
    if [[ "$aTitle" == "${bookTitle[$c]}" ]]; then 

     if [[ "$aAuthor" == "${author[$c]}" ]]; then  

      found=true 

     fi 

    fi 
done 

echo $found 
} 

#author[$i]=$aAut} 

./menu.sh: line 43: syntax error near unexpected token `done' 
./menu.sh: line 43: ` done' 

Answer 1

您for loop是錯誤的標準POSIX外殼！ 這不是C/C++，它的外殼和這裏的通常的方式做到這一點：

for c in $(seq 0 $i); do 
    ... 
done 

和下面的結構：

typeset -i i END 
for ((i=0;i<END;++i)); do echo $i; done 

是bash的具體和下面給出任何錯誤：

#!/bin/bash 

function add_new_book() { 
    echo "1) add_new_book" 

    found=false 

    echo -n "Title: " 
    read aTitle 
    echo -n "Author: " 
    read aAuthor 

    # declare c and END as integers 
    typeset -i c END 
    let END=5 # use END instead of $i if $i is not defined! 
    for ((c=0;c<i;++c)); do 

     if [[ "$aTitle" == "${bookTitle[$c]}" ]]; then 

      if [[ "$aAuthor" == "${author[$c]}" ]]; then  

       found=true 

      fi 

     fi 
    done 

    echo $found 
} 

add_new_book 

所以我想你可能一直試圖用/bin/sh而不是/bin/bash來運行這個例子，它可能是另一個shell，如dash或bsh。在for循環條件下，您也不能使用$i，但在中不應使用i。

N.B .:在我給出的腳本中，仍然存在錯誤：$i未在腳本的上下文中定義！

Answer 2

此示例腳本可能會對您有所幫助。

bookTitle="linux,c,c++,java" 
author="dony,jhone,stuart,mohan" 

function add_new_book() 
{ 
    IFS=', ' 
    read -a bookTitle <<< "$bookTitle" 
    read -a author <<< "$author" 

    echo "1) add_new_book" 

    found=false 

    echo -n "Title: " 
    read aTitle 
    echo -n "Author: " 
    read aAuthor 


    for index in "${!bookTitle[@]}" 
    do 
     if [[ "$aTitle" == "${bookTitle[index]}" ]] 
     then  

      if [[ "$aAuthor" == "${author[index]}" ]] 
      then  
        found=true 
      fi 
     fi 
    done 

    echo $found 
}