更新MYSQL記錄錯誤

Question

我正在腳本上更新記錄。該腳本在我看來很好，我也收到了成功消息，但該記錄未在數據庫中更新。請幫我解決這個問題。

這是我的表單頁面。

<!-- Inquiry Table Stars here --> 

<?php 
$id=$_GET['id']; 
$sql = "Select * From inquiry WHERE id='$id'"; 
$result = mysql_query($sql); 


?> 

<?php 
while($row=mysql_fetch_array($result)) 
{ 
$name = $row['cname'];; 
$email = $row['email'];; 
$phone = $row['phone'];; 
$sdate = $row['sdate'];; 
$edate = $row['edate'];; 
$fdate = $row['fdate'];; 

?> 




<!-- Code Begins --> 
<center> 
<div class="vpb_main_wrapper"> 

<br clear="all"> 
<form method="post" action="edit_ac.php"> 
<h2 align="left" style="margin-top:0px;">Edit Operator</h2><br /> 

<div align="left" style="font-family:Verdana, Geneva, sans-serif; font-size:11px; margin-bottom:10px;">Edit operator Details.</div><br /> 

<div style="width:115px; padding-top:10px;float:left;" align="left"> Full Name:</div> 
<div style="width:300px;float:left;" align="left"><input type="text" name="cname" id="cname" value="<?php echo $name; ?>" class="vpb_textAreaBoxInputs" required> 
</div><br clear="all"><br clear="all"> 

<div style="width:115px; padding-top:10px;float:left;" align="left"> Email:</div> 
<div style="width:300px;float:left;" align="left"><input type="text" name="email" id="email" value="<?php echo $email; ?>" class="vpb_textAreaBoxInputs" required> 
</div><br clear="all"><br clear="all"> 


<div style="width:115px; padding-top:10px;float:left;" align="left">Mobile:</div> 
<div style="width:300px;float:left;" align="left"><input type="text" name="phone" id="phone" value="<?php echo $phone; ?>" required class="vpb_textAreaBoxInputs"> 
</div><br clear="all"><br clear="all"> 


<div style="width:115px; padding-top:10px;float:left;" align="left">Start Date:</div> 
<div style="width:300px;float:left;" align="left"><input type="text" name="sdate" id="sdate" value="<?php echo $sdate; ?>" required class="vpb_textAreaBoxInputs"> 
</div><br clear="all"><br clear="all"> 


<div style="width:115px; padding-top:10px;float:left;" align="left">End Date:</div> 
<div style="width:300px;float:left;" align="left"><input type="text" name="edate" id="edate" value="<?php echo $edate; ?>" required class="vpb_textAreaBoxInputs"> 
</div><br clear="all"><br clear="all"> 


<div style="width:115px; padding-top:10px;float:left;" align="left">Date of Journey:</div> 
<div style="width:300px;float:left;" align="left"><input type="text" name="fdate" id="fdate" value="<?php echo $fdate; ?>" class="vpb_textAreaBoxInputs" required> 
</div><br clear="all"><br clear="all"> 

<input name="id" type="hidden" id="id" value="<?php echo $row['id']; ?>"> 

<div style="width:115px; padding-top:10px;float:left;" align="left">&nbsp;</div> 
<div style="width:300px;float:left;" align="left"> 
<input type="submit" name="submit" id="submit" value="Submit" style="margin-left: 100px" class="vpb_general_button"> 

</div> 

</form> 
<br clear="all"><br clear="all"> 

</div><?php } ?> 
</center> 
<!-- Code Ends --> 


<!-- Inquiry Table Ends here --> 

，這裏是我的edit_ac.php

<?php 
$host="localhost"; // Host name 
$username="root"; // Mysql username 
$password=""; // Mysql password 
$db_name="pro1"; // Database name 

// Connect to server and select database. 
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB"); 

$name = $_POST['cname']; 
$email = $_POST['email']; 
$phone = $_POST['phone']; 
$sdate = $_POST['sdate']; 
$edate = $_POST['edate']; 
$fdate = $_POST['fdate']; 

// update data in mysql database 
$sql="UPDATE inquiry SET 
     cname = '$name', 
     email = '$email', 
     phone = '$phone', 
     sdate = '$sdate', 
     edate = '$edate', 
     fdate = '$fdate' 
     WHERE id='$id'"; 

$result=mysql_query($sql); 

// if successfully updated. 
if($result){ 
echo "Successfull"; 

} 

else { 
echo "Error"; 
} 

?> 

它顯示 「0記錄更新成功」。所以它沒有在數據庫中更新。什麼問題請幫助。

Answer 1

的問題，我認爲，是你在這兩種情況下不及格$id變量來查詢正確：

你這樣做：

WHERE id='$id'" 

您應該：

WHERE id=" . $id ."" 

編輯1：嘗試通過打印檢查$id變量，如果你真的擁有它：

var_dump($id); 

編輯2：

不要與其他變量的其餘部分：

$sql = "UPDATE 
      inquiry 
     SET 
      cname = " . $name . ", 
      email = " . $email . ", 
      phone = " . $phone . ", 
      sdate = " . $sdate . ", 
      edate = " . $edate . ", 
      fdate = " . $fdate . " 
     WHERE 
      id=" . $id . ""; 

也可以嘗試印刷和檢查，如果你真的得到$name, $email, $phone和等。

Answer 2

商店中的Session中的id值，以便您可以在不同的頁面上使用它。這裏編輯文件沒有ID。

希望它有幫助。

Answer 3

您沒有聲明$ id變量。我添加了這一行：$ id = $ _POST ['id'];

無論如何，mysql函數已被棄用：改爲使用mysqli。

<?php 
$host="localhost"; // Host name 
$username="root"; // Mysql username 
$password=""; // Mysql password 
$db_name="pro1"; // Database name 

// Connect to server and select database. 
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB"); 

$id = $_POST['id']; 
$name = $_POST['cname']; 
$email = $_POST['email']; 
$phone = $_POST['phone']; 
$sdate = $_POST['sdate']; 
$edate = $_POST['edate']; 
$fdate = $_POST['fdate']; 

// update data in mysql database 
$sql="UPDATE inquiry SET 
    cname = '$name', 
    email = '$email', 
    phone = '$phone', 
    sdate = '$sdate', 
    edate = '$edate', 
    fdate = '$fdate' 
    WHERE id='$id'"; 

$result=mysql_query($sql); 

// if successfully updated. 
if($result){ 
echo "Successfull"; 

} 

else { 
echo "Error"; 
} 

?>