LARAVEL爲foreach（）循環提供的無效參數

Question

我有一個Session::get('employee_leave_tag');，它包含payroll_leave_employee_id，因爲data不僅是我使用的一個foreach循環。但是我有一個錯誤的foreach提供

無效的參數（）

有人可以幫助我什麼原因爲什麼我收到這個錯誤？謝謝。

 public function get_session_leave_tagv2() 
    { 
      $employee = [0 => 0]; 
      if(Session::has('employee_leave_tag')) 
      { 
       $employee = Session::get('employee_leave_tag'); 
      } 

      $empdata = array(); 
      foreach($employee as $emp) 
      { 

       $employee_id = Tbl_payroll_leave_employeev2::select('payroll_employee_id') 
                  ->join('tbl_payroll_leave_schedulev2','tbl_payroll_leave_employee_v2.payroll_leave_employee_id','=','tbl_payroll_leave_schedulev2.payroll_leave_employee_id') 
                  ->where('tbl_payroll_leave_schedulev2.payroll_leave_employee_id',$emp) 
                  ->distinct() 
                  ->get(); 

        if(count($employee_id) == 0) 
        { 
         $empa = Tbl_payroll_employee_basic::join('tbl_payroll_leave_employee_v2','tbl_payroll_leave_employee_v2.payroll_employee_id','=','tbl_payroll_employee_basic.payroll_employee_id')->whereIn('tbl_payroll_leave_employee_v2.payroll_leave_employee_id',$emp)->get(); 
         array_push($empdata,$empa); 
        } 
        else 
        { 
         $empb = Tbl_payroll_leave_schedulev2::getallemployeeleavedata($employee_id)->get(); 
         array_push($empdata,$empb); 
        }        

      } 

      $data['new_record'] = $empdata; 

      return json_encode($data); 
    } 

Answer 1

您需要對代碼進行兩處更改。

第一變化： 你的數組聲明$employee = array();或$employee[];

第二變化： 它始終是一個很好的做法，以檢查是否使用可變if條件我們寫foreach循環之前是一個數組，而不是空。它將使我們擺脫您面臨的錯誤。

if(is_array($employee) && !empty($employee)) 
{ 
    foreach($employee as $emp) 
    { 
    } 
}