我有兩個mySql查詢來從數據庫中獲取結果。我正試圖將它們結合在一起。mySql結合兩個SELECT查詢JOIN
查詢1:
SELECT userEwallets.id as ewalletId, users.id as userId , money_repositories.money as money, a.nestedUserId
FROM userEwallets
JOIN users ON users.id = userEwallets.userId
JOIN money_repositories ON userEwallets.id = money_repositories.ewalletId
WHERE ewalletNumber = 'SHIRR937303656'
查詢2:
SELECT nested.id as nestedUserId
FROM userEwallets as nested
JOIN users ON users.id = nested.userId
JOIN money_repositories ON nested.id = money_repositories.ewalletId
WHERE ewalletNumber = 'SHIRR9122331743'
,然後我的組合命令:
SELECT userEwallets.id as ewalletId, users.id as userId , money_repositories.money as money, a.nestedUserId
FROM (
SELECT nested.id as nestedUserId
FROM userEwallets as nested
JOIN users ON users.id = nested.userId
JOIN money_repositories ON nested.id = money_repositories.ewalletId
WHERE ewalletNumber = 'SHIRR912233'
) as a
JOIN users ON users.id = userEwallets.userId
JOIN money_repositories ON userEwallets.id = money_repositories.ewalletId
WHERE ewalletNumber = 'SHIRR93730'
我得到這個錯誤:
#1054 - Unknown column 'userEwallets.id' in 'field list'
這兩個命令都相同,但是他們在where
子句簡單差作爲ewalletNumber
WITH數據庫結構UPDATE
money_repositories
表:
CREATE TABLE IF NOT EXISTS `money_repositories` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`userId` int(11) NOT NULL,
`ewalletId` int(11) NOT NULL,
`money` int(11) NOT NULL,
`createdAt` int(11) NOT NULL,
`updatedAt` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_persian_ci AUTO_INCREMENT=4 ;
userEwallets
表:
CREATE TABLE IF NOT EXISTS `userEwallets` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`userId` int(11) NOT NULL,
`ewalletNumber` varchar(15) COLLATE utf8_persian_ci NOT NULL,
`currencySymbol` varchar(5) COLLATE utf8_persian_ci NOT NULL,
`createdAt` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`updatedAt` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_persian_ci AUTO_INCREMENT=7 ;
users
表:
CREATE TABLE IF NOT EXISTS `users` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`username` varchar(20) COLLATE utf8_persian_ci NOT NULL,
`password` varchar(65) COLLATE utf8_persian_ci NOT NULL,
`name` varchar(20) COLLATE utf8_persian_ci NOT NULL,
`family` varchar(20) COLLATE utf8_persian_ci NOT NULL,
`birthDay` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00' ON UPDATE CURRENT_TIMESTAMP,
`email` varchar(20) COLLATE utf8_persian_ci NOT NULL,
`mobileNumber` varchar(15) COLLATE utf8_persian_ci NOT NULL,
`verifyCode` varchar(5) COLLATE utf8_persian_ci NOT NULL,
`photoUri` varchar(50) COLLATE utf8_persian_ci NOT NULL,
`ebanNumber` varchar(20) COLLATE utf8_persian_ci NOT NULL,
`status` tinyint(1) NOT NULL,
`createdAt` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
`updatedAt` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_persian_ci AUTO_INCREMENT=35 ;
我收到此錯誤:''where'子句中'未知列'ewalletNumber' –
ewalletNumber列屬於哪個表?如果它屬於'userEwallets',則嘗試'嵌套。ewalletNumber ='SHIRR912233''您在獲取時使用別名。但是你不在別處或選擇情況使用別名。 – bencagri
我再次收到錯誤#1054 - 'where子句'中的未知列'nested.ewalletNumber' –