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我在xsl-fo中創建了一個未定義數量的元素(indtr)的表。 ?使用XSLT創建動態XSL-FO表
我不知道是否有這樣做一個聰明的辦法
這裏是我的XML輸入文件
<pr-levels>
<prs>
<pr_nme><![CDATA[Level 1]]></pr_nme>
<nt><![CDATA[standards:]]></nt>
<b_is>
<indtr id="5684"><![CDATA[cell_1]]></indtr>
<indtr id="5684"><![CDATA[cell_2]]></indtr>
<indtr id="5684"><![CDATA[cell_3]]></indtr>
<indtr id="5684"><![CDATA[cell_4]]></indtr>
</b_is>
</prs>
<prs>
<pr_nme><![CDATA[Level 2]]></pr_nme>
<nt><![CDATA[standards:]]></nt>
<b_is>
<indtr id="5684"><![CDATA[cell_1]]></indtr>
</b_is>
</prs>
<prs>
<pr_nme><![CDATA[Level 3]]></pr_nme>
<nt><![CDATA[standards:]]></nt>
<b_is>
<indtr id="5684"><![CDATA[cell_1]]></indtr>
<indtr id="5684"><![CDATA[cell_2]]></indtr>
</b_is>
</prs>
<prs>
<pr_nme><![CDATA[Level 4]]></pr_nme>
<nt><![CDATA[standards:]]></nt>
<b_is>
<indtr id="5684"><![CDATA[cell_1]]></indtr>
<indtr id="5684"><![CDATA[cell_2]></indtr>
<indtr id="5684"><![CDATA[cell_3]]></indtr>
<indtr id="5684"><![CDATA[cell_4]></indtr>
<indtr id="5684"><![CDATA[cell_5]]></indtr>
<indtr id="5684"><![CDATA[cell_6]]></indtr>
<indtr id="5684"><![CDATA[cell_7]]></indtr>
</b_is>
</prs>
<prs>
<pr_nme><![CDATA[Level 5]]></pr_nme>
<nt><![CDATA[standards:]]></nt>
<b_is>
<indtr id="5684"><![CDATA[cell_1]]></indtr>
<indtr id="5684"><![CDATA[cell_2]]></indtr>
<indtr id="5684"><![CDATA[cell_3]]></indtr>
<indtr id="5684"><![CDATA[cell_4]]></indtr>
<indtr id="5684"><![CDATA[cell_5]]></indtr>
<indtr id="5684"><![CDATA[cell_6]]></indtr>
<indtr id="5684"><![CDATA[cell_7]]></indtr>
<indtr id="5684"><![CDATA[cell_8]]></indtr>
<indtr id="5684"><![CDATA[cell_9]]></indtr>
<indtr id="5684"><![CDATA[cell_10]]></indtr>
<indtr id="5684"><![CDATA[cell_11]]></indtr>
<indtr id="5684"><![CDATA[cell_12]]></indtr>
<indtr id="5684"><![CDATA[cell_13]]></indtr>
<indtr id="5684"><![CDATA[cell_14]]></indtr>
<indtr id="5684"><![CDATA[cell_15]]></indtr>
<indtr id="5684"><![CDATA[cell_16]]></indtr>
<indtr id="5684"><![CDATA[cell_17]]></indtr>
<indtr id="5684"><![CDATA[cell_18]]></indtr>
<indtr id="5684"><![CDATA[cell_19]]></indtr>
</b_is>
</prs>
</pr-levels>
這裏是產生XSL-FO表我的XSLT模板:
<xsl:template match="pr-levels">
<fo:table xsl:use-attribute-sets="table_p" break-after="page" force-page-count="no-force">
<fo:table-column column-number="1" xsl:use-attribute-sets="table_col_p"/>
<fo:table-column column-number="2" xsl:use-attribute-sets="table_col_p"/>
<fo:table-column column-number="3" xsl:use-attribute-sets="table_col_p"/>
<fo:table-column column-number="4" xsl:use-attribute-sets="table_col_p"/>
<fo:table-column column-number="5" xsl:use-attribute-sets="table_col_p"/>
<fo:table-header xsl:use-attribute-sets="table_header">
<xsl:for-each select="prs/pr_nme">
<fo:table-cell>
<fo:block>
<xsl:apply-templates/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-header>
<fo:table-body >
<fo:table-row>
<xsl:for-each select="prs/nt">
<fo:table-cell>
<fo:block xsl:use-attribute-sets="nt" >
<xsl:apply-templates/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
<fo:table-row>
<xsl:for-each select="prs/b_is">
<fo:table-cell padding="1pt">
<fo:block>
<xsl:value-of select="indtr[1]"/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
<fo:table-row>
<xsl:for-each select="prs/b_is">
<fo:table-cell padding="1pt">
<fo:block>
<xsl:value-of select="indtr[2]"/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
<fo:table-row>
<xsl:for-each select="prs/b_is">
<fo:table-cell padding="1pt">
<fo:block>
<xsl:value-of select="indtr[3]"/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
<fo:table-row>
<xsl:for-each select="prs/b_is">
<fo:table-cell padding="1pt">
<fo:block>
<xsl:value-of select="indtr[4]"/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
<fo:table-row>
<xsl:for-each select="prs/b_is">
<fo:table-cell padding="1pt">
<fo:block>
<xsl:value-of select="indtr[5]"/>
</fo:block>
</fo:table-cell>
</xsl:for-each>
</fo:table-row>
</fo:table-body>
</fo:table>
</xsl:template>
有可能是NULL,1,69或在<b_is>
的任何數字,但現在我只是硬編碼的數字。我的問題是我如何動態計數indtrs的數量和在我table.maybe一個XSL中添加行的for循環
________________________________________________________
| level 1 | level 2 | level 3 | level 4 | level 5 |
--------------------------------------------------------
|standards:|standards:|standards:|standards:|standards:|
--------------------------------------------------------
| cell 1 | cell 1 | cell 1 | cell 1 | cell 1 |
--------------------------------------------------------
| cell 2 | cell 2 | cell 2 | cell 2 | cell 2 |
--------------------------------------------------------
| | cell 3 | cell 3 | cell 3 | cell 3 |
--------------------------------------------------------
| | cell 4 | | | cell 4 |
--------------------------------------------------------
| | | | | cell 5 |
--------------------------------------------------------
| | | | | cell 6 |
--------------------------------------------------------
表應該是什麼樣子?我可以看到每個''是一個新表,並且有一個新行,其中一個單元格用於''和''。你想用''和''孩子做什麼? ''應該是一個新行,並且每個''是一個單元格?或者每個''應該是一個單元格的新行? –
嘿@DevNull感謝您的回覆。同一個b_is中的每一個indtr都會在同一列中,我添加了一個示例來幫助您可視化。 – Jimmy
我會盡量在未來幾天內把東西放在一起。 –