如何獲取python列表中每個數字的mod

Question

這段代碼有什麼問題？ （我試圖讓用戶輸入10個整數，然後返回最大奇數，如果沒有勝算，然後返回一份聲明中這樣說）

numbers = raw_input('Enter 10 integers separated by comma ') 
numbers = [numbers.split(',')] 
odds = [x for x in numbers if x%2==1] 

if not odds: 
print "no odd number was entered" 
else: 
print max(odds) 

Answer 1

我猜numbers是str實例的列表。嘗試numbers = [int(n) for n in numbers.split(',')]。

Answer 2

你需要做兩件事情：

1. 在此行中刪除方括號：

   numbers = [numbers.split(',')] 
   

   否則，str.split返回的列表將被放在另一個列表。

2. 將由str.split返回的字符串列表轉換爲整數列表。這可以用map和int來完成：

   numbers = map(int, numbers.split(',')) 
   

   否則，下一行%將被解釋爲字符串格式化，這將引發錯誤：

   Traceback (most recent call last): 
       File ".\t.py", line 3, in <module> 
       odds = [x for x in numbers if x%2==1] 
   TypeError: not all arguments converted during string formatting 
   

---

以下是您的腳本的固定版本：

numbers = raw_input('Enter 10 integers separated by comma ') 
numbers = map(int, numbers.split(',')) 
odds = [x for x in numbers if x%2==1] 

# The Python standard for indentation is 4 spaces 
if not odds: 
    print "no odd number was entered" 
else: 
    print max(odds) 

演示：

>>> numbers = raw_input('Enter 10 integers separated by comma ') 
Enter 10 integers separated by comma 1,2,3,4,5,6,7,8,9,10 
>>> numbers = map(int, numbers.split(',')) 
>>> odds = [x for x in numbers if x%2==1] 
>>> if not odds: 
...  print "no odd number was entered" 
... else: 
...  print max(odds) 
... 
9 
>>>