無法訪問與您的字段名JOB_CODE

喜正試圖驗證是否有我的數據庫中現有的JOB_CODE的時候我會插入一些錯誤信息，但我得到這個無法訪問與您的字段名JOB_CODE

無法訪問的錯誤信息對應於您的字段名稱 JOB_CODE。

這是我的代碼。

控制器

public function create(){ 

      $this->load->library('form_validation'); 
      $this->form_validation->set_rules('JOB_CODE','JOB_CODE','required|trim|callback_if_exist'); 
      $this->form_validation->set_rules('JOB_NAME','Job Name','required|trim'); 

      if($this->form_validation->run()){ 
       $this->load->model('Job_Titles_Model'); 
       $input = array(
        'JOB_CODE' => $this->input->post('JOB_CODE'), 
        'JOB_NAME' => $this->input->post('JOB_NAME') 
        ); 
       $this->Job_Titles_Model->insert($input); 
       $this->add_view(); 

      }else{ 
       $this->add_view(); 
      } 

} 

public function if_exist(){ 

     $this->load->library('form_validation'); 
     $this->load->model('Job_Titles_Model'); 

     if($this->Job_Titles_Model->validate_code()){ 
      return true; 
     }else{ 
      $this->form_validation->set_message('if_exist','Job code already exists.'); 
      return false; 
     } 


    }

模型

public function validate_code(){ 

    $sql = "SELECT * FROM job_titles WHERE JOB_CODE =?"; 
    $data = array('JOB_CODE' => $this->input->post('JOB_CODE')); 
    $query = $this->db->query($sql, $data); 

    if($query->num_rows() == 0){ 
     return true; 
    }else{ 
     return false; 
    }

視圖

<?php 

     echo form_open('Job_Titles/create'); 

     //echo "Job Title Code:"; 
     //echo form_input('JOB_CODE','', 'class ="field"'); 
     //echo "Job Title:"; 
     //echo form_input('JOB_TITLE','', 'class ="field"'); 
    ?> 

    <p> 
     <label class="field" for="JOB_CODE"><span>*</span>Job Code:</label> 
     <input type = "text" name="JOB_CODE" class ="textbox-300"> 
    </p> 
    <p> 
     <label class="field" for="JOB_NAME"><span>*</span>Job Name:</label> 
     <input type = "text" name="JOB_NAME" class ="textbox-300"> 
    </p> 



    <?php 
     echo form_submit('submit','Save'); 
     echo validation_errors(); 
     echo form_close(); 
    ?>

來源

2016-02-26 kev_m

$errs=array('password_check'=>'nice message'); 
$this->form_validation->set_rules('password','password','callback_password_check',$errs);

似乎採取具有函數名作爲字段名稱的數組。 This is codeigniter 3.1.2

來源

2017-01-10 14:15:36 Kursk

無法訪問與您的字段名JOB_CODE

回答

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