2
我有代碼:AWT事件線程中斷
import java.awt.Dimension;
import java.util.Observable;
import java.util.Observer;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.SwingUtilities;
public class Test2 {
JFrame frame = null;
JPanel panel = null;
JButton button = null;
Task task = null;
Indicator indicator = null;
Runnable computation;
public static void main(String[] args) {
new Test2().start();
}
public void start() {
SwingUtilities.invokeLater(new Dialog());
}
private void process1() {
int result = 0;
for (int i=0; i<100000; i++) {
result = (int) Math.ceil(++result + Math.sqrt(result));
System.out.println("proc1 " + result);
}
}
private void process2() {
int result = 0;
for (int i=0; i<100000; i++) {
result = (int) Math.ceil(++result + Math.sqrt(result)*500);
System.out.println("proc2 " + result);
}
}
private class Computation implements Runnable {
public void run() {
process1();
task.setProgress(2);
process2();
task.setProgress(3);
}
}
private class Dialog implements Runnable {
public Dialog() {
}
public void run() {
frame = new JFrame("Test");
panel = new JPanel();
panel.setPreferredSize(new Dimension(300, 200));
frame.getContentPane().add(panel);
button = new JButton("b1");
panel.add(button);
indicator = new Indicator();
task = new Task();
task.addObserver(indicator);
frame.pack();
frame.setVisible(true);
computation = new Computation();
SwingUtilities.invokeLater(computation);
}
}
private class Task extends Observable {
int progress;
public Task() {
}
public void setProgress(int progress) {
this.progress = progress;
setChanged();
notifyObservers();
}
public int getProgress() {
return progress;
}
}
private class Indicator implements Observer {
@Override
public void update(Observable arg0, Object arg1) {
button.setText(((Task)arg0).getProgress()+"");
}
}
}
所以我有兩個耗時的操作(過程1和過程2)。我的目標是在process1完成之後,更新擺動按鈕(請參閱task.setProgress方法)。
問題在於,更新在process1()和process2()完成後執行。
+1 @CHEM_Eugene,我認爲'button.setText(((任務)爲arg0).getProgress()+ 「」);'只調用一次,再有進步的任何更新,但你可以如果我使用兩個SwingWorkers執行process1()和process2(),那麼它們的執行順序是不可預知的,那麼請添加System.out.println,或者將此代碼行包裝到invokeLater() – mKorbel
Andrew Thompson中。我需要process2()遵循process1()。我如何獲得這個? –
使用一個'SwingWorker'來調用'process1()'然後'process2()'(按照這個順序)。雖然我一定誤解了你,因爲這個答案看起來很直觀。 –