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我有一個json技能,我需要從下拉菜單model.skills
多選技巧,我使用multipleSkills()
推送arrayvalues[]
中的選定值,但我不應該將重複值推送到arrayvalues
。不要在數組中推重複對象
JSON:
var skills =
[{"name":{"skillId":1,"skillName":"JAVA"}},
{"name":{"skillId":2,"skillName":"C"}},
{"name":{"skillId":3,"skillName":"DEVOPS"}},
{"name":{"skillId":4,"skillName":"ANGULAR JS"}},
{"name":{"skillId":41,"skillName":"drupal"}},
{"name":{"skillId":42,"skillName":"backbone js"}},
{"name":{"skillId":43,"skillName":"nodejs"}},
{"name":{"skillId":44,"skillName":"phone gap"}},
{"name":{"skillId":45,"skillName":"scala"}},
{"name":{"skillId":46,"skillName":"spark"}}]
HTML:
<input class="form-control1" type="text" name="skills" placeholder="Core Skills"
ng-model="model.Skills" ng-focus="skillsforJobs(model.Skills)"
typeahead ="skill as skill.name.skillName for skill in skills | filter:$viewValue | limitTo:10"
typeahead-on-select="multipleSkills(model.Skills)"
ng-minlength =1 />
JS:
$scope.arrayvalues = [];
$scope.multipleSkills = function(data){
if($scope.arrayvalues.length <1){
$scope.arrayvalues.push(data);
} else if($scope.arrayvalues.length > 0){
if($scope.arrayvalues.indexOf($scope.model.Skills) == -1) {
if($scope.model.Skills != ""){
for(var i=0; i<$scope.arrayvalues.length;i++){
$scope.arrayvalues[i].name.skillId.indexOf(data.name.skillId){
$scope.arrayvalues.push(data);
$scope.model.Skills = "";
}
}
}
}