行插入與複選框

-1

<form method="post" action="insertassign_process.php"> 
      <table class="table table-bordered table-responsive"> 

     <?php 
     echo"<thead> 
       <tr><th>Tenant ID</th> 
        <th>Tenant ZIP</th> 
        <th>Process server ID</th> 
        <th>Process Server Name</th> 
        <th>Phone Nmuber</th> 
        <th>Select Process Server</th> 
        <th>Assign Proces Server</th> 
        </tr> 
       </thead>"; 
     include("connection.php"); 
     extract($_REQUEST); 
      $SQLSELECT = "SELECT * FROM users where zip_codes='$zip'"; 
      $result_set = mysql_query($SQLSELECT) or die(mysql_error()); 
      while($row = mysql_fetch_array($result_set)) 
      { 
      ?> 

       <tr> 
        <td><input type="text" readonly name="t_id[]" value="<?php echo $t_id; ?>"/></td> 
        <td><input type="text" readonly name="zip[]" value="<?php echo $zip; ?>"/></td> 
        <td><input type="text" readonly name="pr_id[]" value="<?php echo $row['id']; ?> "></td> 
        <td><input type="text" readonly name="fullname[]" value="<?php echo $row['first_name'].' '.$row['last_name']; ?>"</td> 
        <td><?php echo $row['phone_no']; ?></td> 
        <td><input type="checkbox" name="name[]" select="selected" value="<?php echo $row["t_id"]; ?>" /></td> 
        <td><input type="radio" name="assign_process" value="1" /></td> 
       </tr> 
      <?php 
      } 
     ?> 

    </table><button type="submit" class="btn btn-primary button-loading" name="submit" data-loading-text="Loading...">Submit</button></form>

現在，當我檢查任何複選框（可以是多選擇），那麼選擇的該行的將被插入另一個表中的數據。我的查詢插入是：

 <?php 
     session_start(); 
     include("connection.php"); 
     extract($_SESSION); 
     extract($_POST); 
     if(isset($_POST["submit"])==true) 
     { 
     $counter = count($_POST["name"]); /* COUNT THE PASSED ON NAME */ 

     for($x=0; $x<=$counter; $x++){ 

     if(!empty($_POST["name"][$x])){ 
     $CUSTOMER_NAME = mysql_real_escape_string($_POST["t_id"][$x]); 
     $PI_ADDRESS = mysql_real_escape_string($_POST["pr_id"][$x]); 


     $qry="INSERT INTO select_process (id,tenant_select_id,process_select_id) VALUES ('','$CUSTOMER_NAME','$PI_ADDRESS')"; 
     mysql_query($qry); 

     } /* END OF CHECKING THE CHECKBOX IF SELECTED */ 

     } /* END OF FOR LOOP */ 
     } 
     else{ 

     echo"error"; 
     } 
     ?>

但是，當我選擇多行或任何然後它只插入第一行數據。

來源

2017-06-05 cloud soft

請停止使用PHP的過時mysql_ API – Strawberry

-1

你試圖插入空值到id，我認爲你的id字段是主鍵，所以它不能重複，我會建議讓你的id鍵主自動增量，並寫下你的代碼 -

<?php 
    session_start(); 
    include("connection.php"); 
    extract($_SESSION); 
    extract($_POST); 
    if(isset($_POST["submit"])==true) 
    { 
    $counter = count($_POST["name"]); /* COUNT THE PASSED ON NAME */ 

    for($x=0; $x<=$counter; $x++){ 

    if(!empty($_POST["name"][$x])){ 
    $CUSTOMER_NAME = mysql_real_escape_string($_POST["t_id"][$x]); 
    $PI_ADDRESS = mysql_real_escape_string($_POST["pr_id"][$x]); 


     $qry="INSERT INTO select_process (tenant_select_id,process_select_id) VALUES ('$CUSTOMER_NAME','$PI_ADDRESS')"; 

    mysql_query($qry); 

    } /* END OF CHECKING THE CHECKBOX IF SELECTED */ 

    } /* END OF FOR LOOP */ 
    } 
    else{ 

    echo"error"; 
    } 
    ?>

來源

2017-06-05 06:38:23

謝謝你的答覆...... $ QRY =「INSERT INTO select_process（ID，tenant_select_id，process_select_id）VALUES（ ''， '$ CUSTOMER_NAME'，」$ PI_ADDRESS '）「這裏的id是主鍵和自動啓動。但問題是一樣的 –

請幫助任何一個....我浪費了4小時這個代碼 –

如果我選擇所有的行，然後它插入正確...但如果少於所有行比只有第一行插入。 –

行插入與複選框

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