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好吧,我要建一些客戶一個基本的圖片上傳和我遇到某種錯誤的,我撕裂了我的頭髮。PHP Image Uploader - 截斷數組後處理?
後,我得到了$ _FILES數組我做了一點處理,使其更容易解析圖像,但後處理我的價值觀被截斷。
以下是有關PHP:
function organizeFilesArray(&$file_post) {
$file_array = array();
$file_count = count($file_post['name']);
$file_keys = array_keys($file_post);
for ($i=0; $i<$file_count; $i++) {
foreach ($file_keys as $key) {
$file_array[$i][$key] = $file_post[$key][$i];
echo "$file_array[$i][$key]";
echo " ... ";
echo "$file_post[$key][$i] ";
}
echo "$file_count ";
}
return $file_array;
}
if(isset($_POST)){
$destinationDirectory = '/Applications/MAMP/htdocs/image_upload/uploads/';
//check if _FILES array is empty or if the file was uploaded via POST
if(!isset($_FILES['ImageFile']) || !is_uploaded_file($_FILES['ImageFile']['tmp_name'])){
die('Something went wrong with Upload!');
}
//clean up the array so I can handle it simply
//$imageArray = organizeFilesArray($_FILES['ImageFile']);
$file_array = organizeFilesArray($_FILES['ImageFile']);
echo" array size pp: " . sizeof($file_array);
foreach($file_array as $file){
//random number to be added after image name
$randomNumber = rand(0, 9999999999);
//access these values by using their index position
//$imageName = str_replace(' ','-',strtolower($file['name']));
$imageName = $file['name']; //get file name
$imageSize = $file['size']; // Obtain original image size
$tempSrc = $file['tmp_name']; // Tmp name of image file stored in PHP tmp folder
$imageType = $file['type']; //Obtain file type, returns "image/png", image/jpeg, text/plain etc.
echo "This is the type before we try: " . $file['type'];
echo "This is the name before we try: " . $file['name'];
echo "This is the size before we try: " . $file['size'];
//make sure filetype is supported
switch(strtolower($imageType)){
case 'image/png':
$createdImage = imagecreatefrompng($file['tmp_name']);
break;
case 'image/gif':
$createdImage = imagecreatefromgif($file['tmp_name']);
break;
case 'image/jpeg':
case 'image/pjpeg':
$createdImage = imagecreatefromjpeg($file['tmp_name']);
break;
default:
die('Unsupported File!:'.$imageType); //output error and exit
}
對不起,在那裏所有的print語句,試圖找出發生了什麼事情。當試圖上載的東西我得到這個(從螢火蟲):
所以..處理後,一切都在我的數組被截斷爲它看起來像第一個字符?任何幫助將不勝感激!
事實旁邊,我最後不得不完全重新編寫的函數,哈哈,這是問題的一部分!謝謝! – dwf 2013-03-06 01:23:31