有COUNT（）= 0的困惑

我想選擇使用內連接到另一個表的行。有COUNT（）= 0的困惑

SELECT COUNT(t3.ID), t3.act, t3.dj_id, t1.ID, 
    t1.name, t1.label_id, t1.date, t1.genre, 
    t1.plink, t1.featana, t1.promo_aktif 
FROM `release` t1 
INNER JOIN `acts` t3 ON t3.release_id = t1.ID 
WHERE t1.ID IN ($lst) AND t1.promo_aktif = 'Active' 
AND t3.act = 'hide' AND t3.dj_id = '$id' 
HAVING COUNT(t3.ID) = 0 
ORDER BY t1.ID DESC 
LIMIT 0,15

在此查詢中，結果爲空。它選擇0行。但我確信有這種條件的行。

查詢需要選擇t1行的時候沒有在t3

我在哪裏錯在此查詢找到的記錄？

感謝

編輯

正確的代碼是

SELECT t3.act, t3.dj_id, t1.ID, 
    t1.name, t1.label_id, t1.date, t1.genre, 
    t1.plink, t1.featana, t1.promo_aktif 
FROM `release` t1 
LEFT JOIN `acts` t3 ON t3.release_id = t1.ID AND t3.act = 'hide' AND t3.dj_id = '$id' 
WHERE t1.ID IN ($lst) AND t1.promo_aktif = 'Active' 
AND t3.release_id is null 
ORDER BY t1.ID DESC 
LIMIT 0,15

來源

2012-02-16 Utku Dalmaz

'查詢需要選擇T1行的時候沒有在t3'找到的記錄---不是不是什麼' INNER JOIN'應該這樣做。 – zerkms 2012-02-16 01:13:31

如何在t3不返回行時選擇t3.act？ – 2012-02-16 01:17:25

幫助你一個忙，並學習在逗號後面使用空格鍵。它可以更容易地告訴你正在使用哪個列（當然，我指的是使用't1.name，t1.label_id，t1.date'而不是't1.name，t1.label_id，t1。日期「。第一種情況下，當您需要稍後返回添加或刪除列時，它的可讀性要高得多，並且使其他人必須閱讀它更容易*） – 2012-02-16 01:19:49

正確的代碼是

SELECT t3.act, t3.dj_id, t1.ID, 
    t1.name, t1.label_id, t1.date, t1.genre, 
    t1.plink, t1.featana, t1.promo_aktif 
FROM `release` t1 
LEFT JOIN `acts` t3 ON t3.release_id = t1.ID AND t3.act = 'hide' AND t3.dj_id = '$id' 
WHERE t1.ID IN ($lst) AND t1.promo_aktif = 'Active' 
AND t3.release_id is null 
ORDER BY t1.ID DESC 
LIMIT 0,15

來源

2012-03-05 07:38:01

試試這個：

SELECT t3.act, t3.dj_id, t1.ID, 
    t1.name, t1.label_id, t1.date, t1.genre, 
    t1.plink, t1.featana, t1.promo_aktif 
FROM `release` t1 
LEFT JOIN `acts` t3 ON t3.release_id = t1.ID 
WHERE t1.ID IN ($lst) AND t1.promo_aktif = 'Active' 
    AND t3.act = 'hide' AND t3.dj_id = '$id' 
      AND t3.release_id is null 
ORDER BY t1.ID DESC 
LIMIT 0,15

不知道你的代碼，我不相信這個條件：t3.dj_id = '$id'

來源

2012-02-16 01:21:18

不起作用。它還顯示在t3 – 2012-02-16 01:23:46

中找到的行仍然不起作用。我看到空的結果。 – 2012-02-16 01:28:22

然後它只是你的過濾器的問題。在你的代碼中必須出現錯誤：'t1.ID IN（$ lst）AND t1.promo_aktif ='Active'AND t3.act ='hide'AND t3.dj_id ='$ id''。通過「錯誤」我的意思是它過濾比它應該更多。刪除所有這些過濾器並逐步添加它們以查找。特別注意't3.dj_id ='$ id'' – 2012-02-16 01:39:37

這應該給你想要的結果：

SELECT t1.ID, 
    t1.name, t1.label_id, t1.date, t1.genre, 
    t1.plink, t1.featana, t1.promo_aktif 
FROM `release` t1 
LEFT JOIN `acts` t3 ON t3.release_id = t1.ID 
WHERE t1.ID IN ($lst) AND t1.promo_aktif = 'Active' 
AND t3.release_id IS NULL 
ORDER BY t1.ID DESC 
LIMIT 0,15

來源

2012-02-16 01:29:08 dgw

有COUNT（）= 0的困惑

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