2012-10-27 160 views
5

我想實現一個httpClient類,這是一個AsyncTask(否則我得到一個異常,因爲我的主線程中有一個連接)。 我想是這樣的:Android Async Http獲取請求

private class execHttpAsync extends AsyncTask <String, String, HttpResponse> 
    { 
     public String resultString; 

     @Override 
     protected HttpResponse doInBackground(String... params) 
     { 
      String url = params[0]; 

      HttpClient httpClient = new DefaultHttpClient(); 
      HttpGet request = new HttpGet(url);   
      request.setHeader("Content-Type", "text/xml"); 
      HttpResponse response; 
      try { 
       response = httpClient.execute(request); 
      } catch (ClientProtocolException e) { 
       // TODO Auto-generated catch block 
       e.printStackTrace(); 
      } catch (IOException e) { 
       // TODO Auto-generated catch block 
       e.printStackTrace(); 
      } 
      return response; 
     } 

     @Override 
     protected void onPostExecute(HttpResponse result) 
     { 
      StringBuffer returned = new StringBuffer(); 

      InputStream content = result.getEntity().getContent(); 
      BufferedReader rd = new BufferedReader(new InputStreamReader(content, "UTF-8"));     
      String line; 
      while ((line = rd.readLine()) != null) 
      { 
       String endOfLine = ""; 
       returned.append(line + endOfLine); 
      } 
      content.close(); 

     String retVal = returned.toString(); 

     try 
     { 
      String header = retVal.substring(0, 1); 
      if (!header.equals("<")) 
       { 
       retVal = retVal.replace(header, ""); 
       } 
     } 
     catch (Exception e) 
     { 
      // TODO: handle exception 
     } 

     resultString = returned.toString(); 

     } 

    } 

但我需要得到最終的響應。我試圖實例化這個類,然後得到響應作爲成員,但沒有解決。 有什麼建議嗎?

+0

你遇到了什麼樣的錯誤?你沒有得到結果嗎?發佈堆棧跟蹤,如果有的話。 –

回答

12

嘗試這種方式

private class DownloadWebPageTask extends AsyncTask<String, Void, String> { 
    @Override 
    protected String doInBackground(String... urls) { 
     String response = ""; 
     for (String url : urls) { 
     DefaultHttpClient client = new DefaultHttpClient(); 
     HttpGet httpGet = new HttpGet(url); 
     try { 
      HttpResponse execute = client.execute(httpGet); 
      InputStream content = execute.getEntity().getContent(); 

      BufferedReader buffer = new BufferedReader(new InputStreamReader(content)); 
      String s = ""; 
      while ((s = buffer.readLine()) != null) { 
      response += s; 
      } 

     } catch (Exception e) { 
      e.printStackTrace(); 
     } 
     } 
     return response; 
    } 

    @Override 
    protected void onPostExecute(String result) { 
     textView.setText(result); 
    } 
    } 
1

這是異步操作,因此類似的東西:

myRetValue = new myAsyncTask.execute(); 

將不會從onPostExecute()分配返回值myRetValue。你

resultString = returned.toString(); 

應該產生具有任何returned.toString()出品分配給resultString變量(我猜你的AsyncTask類的外部聲明,所以基本上你的代碼乍看上去很好。你可能根本不具有returned任何東西。請嘗試在你的AsyncTask代碼中植入一些斷點並檢查它是否真的如你所想的那樣運行。