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我已經完成了根據給定的主類別id獲取子類別的方法。sqlite只返回一條記錄
運行此方法時,它只取一條記錄。我的意思是控制來到
while(sqlite3_step(selectstmt) == SQLITE_ROW)
while
只循環一次。
當執行相同的查詢到SQL瀏覽器能正常工作並獲取結果expected.I不知道爲什麼這個運行功能不工作時
請讓我知道,有什麼問題就出在
- (NSMutableDictionary *) getDataToDisplayTierTwo:(NSString*)dbPath:(NSString*)iD{
NSMutableDictionary *aTierTwoData = [[NSMutableDictionary alloc]init];
if (sqlite3_open([dbPath UTF8String], &database) == SQLITE_OK)
{
NSString *selectSQL = [NSString stringWithFormat: @"select * from sub_categories_reference scr inner join sub_categories ssc on ssc.id = scr.sub_category_id where scr.main_category_id = %@ ",iD];
const char *sql_query_stmt = [selectSQL UTF8String];
sqlite3_stmt *selectstmt;
if(sqlite3_prepare_v2(database, sql_query_stmt, -1, &selectstmt, NULL) == SQLITE_OK)
{
while(sqlite3_step(selectstmt) == SQLITE_ROW)
{
NSLog(@"coming insode");
NSString *aValue = [[NSString alloc] initWithUTF8String:(const char *) sqlite3_column_text(selectstmt, 6)];
NSString *aId = [[NSString alloc] initWithUTF8String:(const char *) sqlite3_column_text(selectstmt, 5)];
[aTierTwoData setObject:aId forKey:aValue];
[aValue release];
[aId release];
NSLog(@"%@ %@ ^^^^^^^^picker value id ", aValue, aId);
}
}
}
else{
//Even though the open call failed, close the database connection to
sqlite3_close(database);
}
return aTierTwoData;
}
感謝您的答覆下面的代碼...什麼是我的代碼 – user198725878 2012-01-12 05:58:05
的問題是它的工作?或不? – Anand 2012-01-12 06:28:01
它不起作用。這也是隻返回一條記錄 – user198725878 2012-01-12 07:01:35