如何使用.net正則表達式來替換這個字符串？

Question

我想換掉這個字符串 2000-12-13T13:59:59+12:00 成爲 2000-12-13 13:59:59

這是可能的？我不能使用普通的替換是因爲這個值是與其他字符串/消息混合在一起，所以我需要搜索模式來取代。

Answer 1

MessageBox.Show(Regex.Replace(
    @"2000-12-13T13:59:59+12:00", 
    @"\b(\d{4}-\d{2}-\d{2})T(\d{2}:\d{2}:\d{2})[+-]\d{2}:\d{2}\b", 
    @"$1 $2" 
)); 

UPD：周圍的模式，一些解釋和一些鏈接添加單詞邊界

\b    - word boundary (not to match "12000-12-13T..." or "X2000-12-13T..." etc, but still to match "(2000-12-13T..." and the like, optional) 
(    - start first capturing ($1) 
\d{4}-\d{2}-\d{2} - date; 4 digits, dash, 2 digits, dash, 2 digits (\d for digit, {N} for exactly N of them) 
)     - end first capturing ($1) 
T     - literal "T" 
(    - start second capturing ($2) 
\d{2}:\d{2}:\d{2} - time; 2 digits, colon, 2 digits, colon, 2 digits 
)     - end second capturing ($2) 
[+-]    - utc offset sign; any of literal "+" or "-" (be careful with "-" inside [], if between other characters it defines range, like [a-z]) 
\d{2}:\d{2}  - utc offset; 2 digits, colon, 2 digits 
\b    - word boundary (not to match "...+12:000" or "...+12:00a" etc, optional) 

資源：on regex in general，on .net，on C# in particular，simple tool for testing

Answer 2

試試這個

\+\d{2}:\d{2}$ 

代碼

string resultString = null; 
try { 
    resultString = Regex.Replace(subjectString, @"\+\d{2}:\d{2}$", "$${retain}", RegexOptions.IgnoreCase); 
} catch (ArgumentException ex) { 
    // Syntax error in the regular expression 
} 

Answer 3

使用正則表達式

(.*)\s(\d{4}\-\d{2}\-\d{2})T(\d{2}:\d{2}:\d{2})\+\d{2}:\d{2}\s(.*) 

和下面的代碼

var regexPattern = @"(.*)\s(\d{4}\-\d{2}\-\d{2})T(\d{2}:\d{2}:\d{2})\+\d{2}:\d{2}\s(.*)"; 

     var dateString = "Some text here 2000-12-13T13:59:59+12:00 And some more text here"; 

     var formattedString = Regex.Replace(dateString, regexPattern, "$2 $3", RegexOptions.IgnoreCase); 

將輸出

2000-12-13 13:59:59 

正則表達式是相當嚴格的，所以你應該能夠從其他文本中抓取它，只要它始終以這種格式存在 - 如果格式根本改變（時間或日期中的單個數字），那麼它不會匹配，但很難說如果沒有上下文，這是一個問題或不是。它還假定該模式僅在文本中出現一次，並且它具有前後空格。