嘗試將我們的Web服務讀入UITableViewController,它只將第一條記錄返回給模擬器。所以希望有人能夠看到代碼並引導我走上正確的道路。最終目標是將其放入UITableViewCell中,這樣我就可以很好地格式化,但只是想要獲取所有記錄。Swift 3.0和web服務
以下是將返回的部分json文件的視圖。
{
"Count":11518,
"Result":[
{
"cuName": "#1",
"charter_Num":
"16328","City":
"Jonesboro",
"State_id": "GA",
"cuName_location": "#1 - Jonesboro, GA"
},
{
"cuName": "@lantec Financial",
"charter_Num": "7965",
"City": "Virginia Beach",
"State_id": "VA",
"cuName_location": "@lantec Financial - Virginia Beach, VA"
}]
}
這是讀取json web服務並嘗試解析並放入表中的代碼。
func get_data_from_url(_ link:String)
{
let url:URL = URL(string: link)!
let session = URLSession.shared
let request = NSMutableURLRequest(url: url)
request.httpMethod = "GET"
request.cachePolicy = NSURLRequest.CachePolicy.reloadIgnoringCacheData
let task = session.dataTask(with: request as URLRequest, completionHandler: {
(
data, response, error) in
guard let _:Data = data, let _:URLResponse = response , error == nil else {
return
}
self.extract_json(data!)
})
task.resume()
}
func extract_json(_ data: Data)
{
let json: Any?
do
{
json = try JSONSerialization.jsonObject(with: data, options: [])
}
catch
{
return
}
//Commented out the following lines because it doesn't return anything when using the modified code that works
//
// guard let data_list = json as? NSArray else
// {
// return
// }
//This code works but only gives me the 1st record back
if let cu_list = try? json as? [String:Any],
let result = cu_list?["Result"] as? [[String:Any]],
let charter_num = result[0]["charter_Num"] as? String,
let value = result[0]["cuName_location"] as? String, result.count > 0 {
TableData.append(value + " (" + charter_num + ")")
} else {
print("bad json - do some recovery")
}
DispatchQueue.main.async(execute: {self.do_table_refresh()})
}
建議:(1)不要在Swift中使用'snake_case'作爲方法和變量名稱。相反,你應該使用較低的'camelCase'。 (2)如果類型可以很容易推斷出來,你不需要指定類型。 (3)大括號應與聲明或聲明內聯,而不是放在新行上。 (4)'''武力打開一個可選項。這應該明智地使用,就好像你試圖強制解包一個具有'nil'值的可選項,你的應用程序會在運行時崩潰。 –
@EricAya,謝謝你的信息。我是一名初學Swift開發人員,所以我試圖找到一些工作,並找到該網站。 – AETechAdm
@RyanH。對我可以對代碼進行的改進提供了很好的反饋,讓它能夠更好地閱讀並希望更好地響應。謝謝 – AETechAdm