C++二維數組到函數

Question

該代碼應該使用2d數組來獲取一週內3只猴子吃掉的食物，並找出平均值，一天中最低食用量，一天中最高。最小函數應該輸出一隻猴子在一天內吃掉的最低食物，並且包括猴子數量，吃過磅數和日數。與最高功能一樣。但它沒有正確計算，我不知道我是否做了錯誤的功能。當我運行它它打印出「的最低量是食用猴子1第1天爲1」，則打印出2，3，4等。我試圖把COUT外循環但然後計數未啓用初始化

#include <iomanip> 
#include <iostream> 
using namespace std; 

//Global Constants 
const int NUM_MONKEYS = 3; // 3 rows 
const int DAYS = 7; // 7 columns 

//Prototypes 
void poundsEaten(double[][DAYS],int, int); 
void averageEaten(double [][DAYS], int, int); 
void least(double [][DAYS], int, int); 
void most(double [][DAYS], int, int); 

int main() 
{ 
//const int NUM_MONKEYS = 3; 
//const int DAYS = 7; 
double foodEaten[NUM_MONKEYS][DAYS]; //Array with 3 rows, 7 columns 

poundsEaten(foodEaten, NUM_MONKEYS, DAYS); 
averageEaten(foodEaten, NUM_MONKEYS, DAYS); 
least(foodEaten, NUM_MONKEYS, DAYS); 
most(foodEaten, NUM_MONKEYS, DAYS); 

system("pause"); 
return 0; 
} 

void poundsEaten(double monkey[][DAYS], int rows, int cols) 
{ 
for(int index = 0; index < rows; index++) 
{ 
    for(int count = 0; count < cols; count++) 
    { 
     cout << "Pounds of food eaten on day " << (count + 1); 
     cout << " by monkey " << (index + 1) << ": "; 
     cin >> monkey[index][count]; 

    } 
} 
} 

void averageEaten(double monkey[][DAYS], int rows, int cols) 
{ 
for(int count = 0; count < cols; count++) 
{ 
    double total = 0; 
    double average; 
    for(int index = 0; index < rows; index++) 
    { 
     total += monkey[index][count]; 

     average = total/rows; 
    } 
    cout << "The average food eaten on day " << (count + 1) 
      <<" is " << average << endl; 

} 
} 

void least(double monkey[][DAYS], int rows, int cols) 
{ 
double lowest = monkey[NUM_MONKEYS][DAYS]; 
for(int index = 0; index < rows; index++) 
{ 
    for(int count = 0; count < cols; count++) 
    { 
     if(monkey[index][count] > lowest) 
      lowest = monkey[index][count]; 

     cout << "The lowest amount of food eaten was monkey number 
         << " " << (index + 1) 
       << " On day " << (count + 1) << " was " << lowest; 
    } 

} 


} 

void most(double monkey[][DAYS], int rows, int cols) 
{ 
double highest = monkey[NUM_MONKEYS][DAYS]; 
for(int index = 0; index < rows; index++) 
{ 
    for(int count = 0; count < cols; count++) 
    { 
     if(monkey[index][count] > highest) 
      highest = monkey[index][count]; 

    cout << "The highest amount of food eaten was monkey number" 
     << (index + 1) << " on day " << (count + 1) << " was " 
        << highest; 
    } 
} 


} 

Answer 1

從least功能：

if(monkey[index][count] > lowest) 
    lowest = monkey[index][count]; 

在比較，我敢肯定，你的意思是<而不是>。

您還應該保存索引並在循環後打印，並且這適用於least和most。