C++分段故障switch語句CIN

-2

string shapename; 
bool warpspace; 
const int size = 100; 
ShapeTwoD shape2D[size]; // ShapeTwoD is a parent class 
int number =0; 
static int count = 0; 

while(choice !=999) 
{ 

    switch(choice) 
    { 
     case 1: 
     { 
      cout<<"[Input sensor data]"<<endl; 
      cout<<"Please enter name of Shape:"; 
      cin>>shapename; 
      shape2D[size].setName(shapename); //segmentation fault 
      cout<<"Please enter special type:"; 
      cin>>warpspace; 
      shape2D[size].setContainsWarpSpace(warpspace); 
      cin.clear(); 
      cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n'); 
      if(shapename == "Square" || shapename == "square") 
       { square.setSquareCord(); count++; } 
      if(shapename == "Rectangle" || shapename == "rectangle") 
       { rect.setRectangleCord(); count++; } 
      mainmenu(); 
      cin>>number; 
      option(number); 
     }break;//there are still multiple cases 
    } 
}

當我嘗試編譯並運行這段代碼，它給了我分割錯誤之後我進入形狀please enter name of shape :我做了什麼錯在這裏？

來源

2016-10-30 what

解決這樣的問題的合適的工具是調試器。在*堆棧溢出問題之前，您應該逐行執行您的代碼。如需更多幫助，請閱讀[如何調試小程序（由Eric Lippert撰寫）]（https://ericlippert.com/2014/03/05/how-to-debug-small-programs/）。至少，您應該\編輯您的問題，以包含一個[最小，完整和可驗證]（http://stackoverflow.com/help/mcve）示例，該示例再現了您的問題，以及您在調試器。 –

您正在訪問出側陣列邊界：

shape2D[size]. 
     ^^^^

有效陣列索引是從0到大小-1

來源

2016-10-30 10:40:47 4386427

C++分段故障switch語句CIN

回答

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