在CakePHP中進行Ajax調用

我想在CakePHP中進行Ajax調用。第一個調用工作正常，它呈現另一個Ajax提交按鈕的視圖。下面的代碼是在第一視圖：在CakePHP中進行Ajax調用

echo $this->Js->submit('LOAD COMMENTS',array(
       'url'=>array(
        'controller'=>'Nominees', 
        'action'=>'load_comments' 
        ), 
       'before'=>$this->Js->get('#sending')->effect('fadeIn'), 
       'success'=>$this->Js->get('#sending')->effect('fadeOut'), 
       'update'=>'#comments' 
       )); 
echo $this->Form->end();

在代理人控制器我有

public $components = array('RequestHandler'); 
/*Load comments for the nominee using ajax*/ 
public function load_comments(){ 

    if(!empty($this->request->data)){ 

     /* Demoting Irrelevant comments. 
Only triggered if the demote comment button is clicked.*/ 
     if(isset($this->request->data['Nominee']['comment_nominee_id'])){ 
      $comment_id = $this->request->data['Nominee']['comment_nominee_id']; 
      $this->Nominee->updateAll(
      array('Nominee.status' =>0), 
      array('Nominee.id'=>$comment_id)); 
     } 

     $userNumber = $this->request->data['Nominee']['number']; 
     $award_id = $this->request->data['Nominee']['award']; 
     $dt = date('Y'); 
     $nominationInfor = $this->Nominee->find('all',array(
          'conditions' => array('Nominee.reg_number'=>$studNumber,'Nominee.year'=>$dt,'Nominee.award_id'=>$award_id,'Nominee.status'=>1), 
          'recursive' => -1 
          )); 
     if(empty($nominationInfor)){ 
      $this->Session->setFlash(__('No Nomination Information Available.')); 
      $this->redirect(array('action' => 'choose_category')); 
     } 
     $this->set(compact('nominationInfor','userNumber','award_id')); 

     if($this->request->isAjax()){ 

      $this->render('load_comments','ajax'); 
     } 

    } 
}

Load_comments，在如此被所調用的圖，具有以下所示的具有視圖代碼一個Ajax按鈕：

echo $this->Js->submit('Demote Comment',array(

       'url'=>array(
        'controller'=>'AwardNominees', 
        'action'=>'load_comments' 
        ), 
       'before'=>$this->Js->get('#demot')->effect('fadeIn'), 
       'success'=>$this->Js->get('#demot')->effect('fadeOut'), 
       'update'=>'#comments' 
       )); 

      echo $this->Form->end();

當點擊了降級評論按鈕，

debug($this->request->isAjax());

返回false，但如果LOAD備註點擊

debug($this->request->isAjax());

返回true。這個想法是當點擊加載評論時，評論被加載，然後單擊降級評論（這是對評論的按鈕），我想要進行Ajax調用刪除其評論。非常感謝您的幫助。

來源

2014-04-22 Bongani Masuku

我想你忘了添加'echo $ this-> Js-> writeBuffer（）;'在你的視圖的末尾 – noslone

爲什麼RequestHandler？它將在未來貶值... –

嘗試使用'$ this-> request-> isAjax（）;'用完整的控制器代碼更新你的問題？它很難理解這個小代碼正在發生什麼.. –

我終於找到了其中i是參考去錯到this

在我的提交按鈕我增加「緩衝」 =>假與我的回調函數數組中從而最終提交是如下所示

   echo $this->Js->submit('Demote Comment',array(
        'url'=>array(
        'controller'=>'AwardNominees', 
        'action'=>'load_comments' 
        ), 
       'before'=>$this->Js->get('#demot')->effect('fadeIn'), 
       'success'=>$this->Js->get('#demot')->effect('fadeOut'), 
       'update'=>'#comments', 
       'buffer' => false 
       ));

我把不同的id放在我創建的窗體上。這讓我的代碼按預期工作。 :-)

來源

2014-04-23 14:01:41

在CakePHP中進行Ajax調用

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