2010-08-02 42 views
18

我只想從我的字符串打開一個URL 我的字符串已具有URL我只是想在UIWebView如何從字符串中的WebView打開網址爲iPhone

myString=http://maps.google.com/maps?zoom=8&sensor=false&lci=transit&layer=traffic&saddr=1.31224,103.865&daddr=1.310664,103.857132 

NSString *urlString = [myString absoluteString]; 
NSString *urlAddress =myString;// 
NSURL *url = [NSURL URLWithString:urlString ]; 

NSLog(@" url is %@",url); its null 
//URL Requst Object 
NSURLRequest *requestObj = [NSURLRequest requestWithURL:url]; 


NSLog(@" url req is %@",url); 
//Load the request in the UIWebView. 
[webe loadRequest:requestObj]; 

展示我得到這個錯誤

se&lci=transit&layer=traffic&saddr=1.31224,103.865&daddr=1.310664,103.857132 
2010-08-02 13:20:08.253 Wat2Eat[5332:207] *** -[NSCFString absoluteString]: unrecognized selector sent to instance 0x1ac570 
2010-08-02 13:20:08.267 Wat2Eat[5332:207] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** -[NSCFString absoluteString]: unrecognized selector sent to instance 0x1ac570' 
2010-08-02 13:20:08.283 Wat2Eat[5332:207] Stack: (

回答

49

添加到您的方法:

NSString *urlAddress = @"http://myurl.com"; 

//Create a URL object. 
NSURL *url = [NSURL URLWithString:urlAddress]; 

//URL Requst Object 
NSURLRequest *requestObj = [NSURLRequest requestWithURL:url]; 

//Load the request in the UIWebView. 
[detailWebView loadRequest:requestObj]; 
1
- (void)viewDidLoad 
{ 
[super viewDidLoad]; 
// Do any additional setup after loading the view. 
NSURL *websiteUrl = [NSURL URLWithString:@"http://www.google.com"]; 
NSURLRequest *urlRequest = [NSURLRequest requestWithURL:websiteUrl]; 
[myWebView loadRequest:urlRequest]; 
} 
+0

雖然這段代碼可能會回答這個問題,但它沒有提供任何上下文來解釋如何或爲什麼。考慮增加一兩句話來解釋你的答案。 – brandonscript 2016-10-11 17:20:17