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我必須編寫一個程序,按字母順序排序名稱,同時刪除重複項並計算名稱出現的次數並將其全部大寫。我和我的合作伙伴一直在研究這個問題,並且沒有辦法讓排序方法正常工作,讓程序查找並計算名稱出現的時間。我們必須使用某些方法來做到這一點...我把這個pdf放在底部。我真的很想明白什麼是錯的,爲什麼輸出不正確。我的排序方法和查找/計數方法搞砸了,我不知道什麼是錯的?
public class Names {
/**
* @param args the command line arguments
*/
static ArrayList<String> fnArray = new ArrayList<String>();
static ArrayList<String> lnArray = new ArrayList<String>();
public static void main(String[] args) throws IOException {
// TODO code application logic here
getNames(fnArray, lnArray);
sort(lnArray);
find(fnArray,1);
capitalize(fnArray,lnArray);
}
public static void getNames(ArrayList<String> fn, ArrayList<String> ln) throws IOException {
Scanner kb = new Scanner(System.in);
System.out.println("What file would you like to read from ?: ");
String n = kb.next();
File inputFile = new File(n);
Scanner in = new Scanner(inputFile);
while (in.hasNext()) {
String firstName = in.next();
fn.add(firstName);
String lastName = in.next();
ln.add(lastName);
}
for (int i = 0; i < fnArray.size(); i++) {
System.out.println(lnArray.get(i) + " " + fnArray.get(i));
}
}
public static void capitalize(ArrayList<String> fnArray, ArrayList<String> lnArray) {
String capfn = " ";
String capln = " ";
int i = 0;
int j = 0;
System.out.println("****************Names***************");
while (i < fnArray.size() && j < lnArray.size()) {
capfn = fnArray.get(i);
capln = lnArray.get(j);
String capFname = capfn.substring(0, 1).toUpperCase() + capfn.substring(1).toLowerCase();
String capLname = capln.substring(0, 1).toUpperCase() + capln.substring(1).toLowerCase();
fnArray.set(i, capFname);
lnArray.set(i, capLname);
System.out.println(lnArray.get(j) + ", " + fnArray.get(i));
i++;
j++;
}
}
public static void display(ArrayList<String> names) {
for (int i = 0; i < names.size(); i++) {
System.out.println(names.get(i));
}
}
public static int find(String s, ArrayList<String> a) {
int count = 0;
for (String str : a) {
if (str.equalsIgnoreCase(s))
count++;
}
return count; }
public static void removeDuplicates(ArrayList<String> s) {
for (int j = 0; j < s.size(); j++) {
int i = -1;
while ((i = find(s, j)) >= 0) {
s.remove(i);
}
}
}
public static void backwards(ArrayList<String> names) {
for (int i = names.size() - 1; i > 0; i--) {
names.get(i);
for (int j = 0; j < names.size(); i++) {
if ((names.get(i).equals(names.get(j)))) {
names.remove(i);
}
}
}
}
public static void sort(ArrayList<String> array) {
for (int i = 1; i < array.size(); i++) {
// find the index of the ith smallest value
int s = i - 1;
for (int j = i; j < array.size(); j++) {
if (array.get(j).compareTo(array.get(s)) < 0) {
s = j;
}
}
// swap the ith smallest value into entry i-1
String temp = array.get(i - 1);
array.set(i - 1, array.get(s));
array.set(s, temp);
}
}
public static void showUnique(ArrayList<String> names){
System.out.println("Unique name list contains:");
for(int i=0 ;i< names.size() ;i++){
System.out.println(lnArray.get(i) + " " + fnArray.get(i));
}
}}
謝謝你的迴應!問題是我們不能使用任何.sort方法,我們必須在public static void sort(ArrayList名稱)下使用它,它必須是嵌套循環,它必須引用存儲在文本文件中的數組列表。 –
@AmyTenorio我已經更新了答案,以包含更容易解釋的排序版本。你能試試嗎? – Pavan