我想創建一個網站,顯示圖片和一些關於圖片作爲個人學習項目的信息。我遇到的問題不一定是從sql查詢,但分頁。我通過代碼去了,並意識到它是由$頁面所導致的,並開始$,但我不知道如何解決它 的代碼是分頁和SQL查詢php分頁不顯示sql數據
<?php
include ('config/db_connect.php');
/* this is for the pages counter main */
// number of pages
$per_page =4;
//query pages
$pages_query = mysql_query("select count('track_id') from music_db");
$pages = ceil(mysql_result($pages_query, 0)/$per_page);
$page = (isset ($_GET['page'])) ? (int)$_GET['page'] : 1;
$start = ($page - 1) * $per_page;
$music_db_query = "select * from music_db limit $start , $per_page";
$music_db_execute = mysql_query($music_db_query);
while($row = mysql_fetch_array($music_db_execute)) {
echo '<link rel="stylesheet" type="text/css" href="css/music.css">';
echo '<div style="background-color:#3a3a3a;">';
echo '<div class="medium-12 columns">';
echo '<article class="mainholder">';
echo '<div class="imageholder"><a href="#"><img src="'.$row['track_art'].'"/></a></div>';
echo '<div class="maindetails"><a href="#"><h5 style="color:white;">'.$row['track_title'].': '.$row['track_artist'].'</h5></a></div>';
$com = $row['track_comments'];
$comred =readMoreFunction($com);
echo '<div class="comments"><a style=" color:white;" href="#"><p>'.$comred .'</p></a></div>';
echo '</article>';
echo '</div>';
echo '</div>';
}
function readMoreFunction($story_desc,$link,$targetFile,$id) {
//Number of characters to show
$chars =210;
$story_desc = substr($story_desc,0,$chars);
$story_desc = substr($story_desc,0,strrpos($story_desc,' '));
$story_desc = $story_desc." <a href='$link?$targetFile=$id'>Read More...</p> </a>";
return $story_desc;
}
if($pages >= 1) {
for($x=1; $x<=$pages; $x++){
echo '<a href ="$page='.$x.'">'.$x.'</a> ';
}
}
mysql_close();
?>
你得到了什麼? – Phoenix
數據不顯示,但分頁顯示的是鏈接[link](http:// http://learn4max.byethost10.com/index.php?page = music)。請檢查看看 – dziedzorm