我在通過FTP上傳文件到我的VPS(centos 6 64位)時遇到了一些麻煩。我正在使用的FTP被稱爲Pure-FTPD,並試圖使用Java上傳圖像。錯誤代碼我得到的是當通過FTP上傳文件到VPS時MalformedURLException
java.net.MalformedURLException:對於輸入字符串:在java.net.URL中的 「VPS經過此地 @ 9X.XXX.2XX.X8」 (來源不明) (Unknown Source) at java.net.URL。(Unknown Source) at FtpUrlUpload.main(FtpUrlUpload.java:25) 引起來自:java.lang.NumberFormatException:對於輸入字符串:「 VPS PASS HERE @ 9X.XXX.2XX.X8「 at java.lang.NumberFormatException.forInputString(Unknown Source) at java.lang.Integer.parseInt(Unknown Source) 在java.lang.Integer.parseInt(來源不明) 在java.net.URLStreamHandler.parseURL(來源不明) ... 4個
這裏是我的全部代碼。
import java.io.FileInputStream;
import java.io.IOException;
import java.io.OutputStream;
import java.net.URL;
import java.net.URLConnection;
public class FtpUrlUpload {
private static final int BUFFER_SIZE = 4096;
public static void main(String[] args) {
String ftpUrl = "ftp://%s:%[email protected]%s/%s;type=i";
String host = "9X.XXX.2XX.X8";
String user = "VPS USERNAME HERE";
String pass = "VPS PASS HERE";
String filePath = "C:\\Users\\user\\desktop\\Untitled.png";
String uploadPath = "public_html/Untitled.png";
ftpUrl = String.format(ftpUrl, user, pass, host, uploadPath);
System.out.println("Upload URL: " + ftpUrl);
try {
URL url = new URL(ftpUrl);
URLConnection conn = url.openConnection();
OutputStream outputStream = conn.getOutputStream();
FileInputStream inputStream = new FileInputStream(filePath);
byte[] buffer = new byte[BUFFER_SIZE];
int bytesRead = -1;
while ((bytesRead = inputStream.read(buffer)) != -1) {
outputStream.write(buffer, 0, bytesRead);
}
inputStream.close();
outputStream.close();
System.out.println("File uploaded");
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
嘗試使用URI.toURL有一個在用戶名沒有空格/通過它的一個短語。你也可以在這行中使用URI.toURL():ftpUrl = String.format(ftpUrl,user,pass,host,uploadPath);爲用戶和通行證? – user2526311