2
我想改變下面的bash函數來執行每個命令參數。但是當我運行這個腳本時,第一個echo會按照預期工作,但第二個echo嘗試附加到scratch.txt文件並不會真正執行。它只是回顯到提示中。bash腳本如何從變量執行命令
#!/bin/sh
clear
function each(){
while read line; do
for cmd in "[email protected]"; do
cmd=${cmd//%/$line}
printf "%s\n" "$cmd"
$cmd
done
done
}
# pipe in the text file and run both commands
# on each line of the file
cat scratch.txt | each 'echo %' 'echo -e "%" >> "scratch.txt"'
exit 0
如何獲取$ cmd變量作爲命令執行?
我發現從2回答這裏的原代碼: xargs with multiple commands as argument
使用'eval「$ cmd」' –