生成多級JSON

Question

我有一個對象數組，每個對象都包含一個不確定長度的位置和鏈接數組。我如何創建一個帶有循環的多級JSON對象？

最終JSON應該像

item1: [ 
    { "location": [ 
     {"latitude": value, "longitude": value, "stopNum": value, "fileName": value } 
    ], 
    "links": [ 
     {"latitude": value, "longitude": value, "stopNum": value, "fileName": value }, 
     {"latitude": value, "longitude": value, "stopNum": value, "fileName": value }, 
     {"latitude": value, "longitude": value, "stopNum": value, "fileName": value } 
    ] 
    } 
], 
item2: [ //repeat of above ] 

我遇到的問題是如何正確地形成的對象。該數組包含的對象定義爲

function Links(){ 
    this.location = null; 
    this.links= []; 

    function getLocation(){ 
    return location; 
    } 
    function setLocation(marker){ 
    this.location = marker; 
    } 

    function getLinks(){ 
    return links; 
    } 
} 

我目前的解決方案是

var json=[]; 
var linkData; 
for (var i=0; i < tourList.length; i++){ 
    var data = tourList[i]; 
    //create new child array for insertion 
    var child=[]; 

    //push location marker data 
    child.push({ 
    latitude: data.location.position.$a, 
    longitude: data.location.position.ab, 
    stopNum: i, 
    filename: data.location.title 
    }); 

    //add associated link data 
    for (var j=0; j<data.links.length; j++){ 
    linkData = data.links[i]; 
    child.push({ 
     latitude: linkData.position.$a, 
     longitude: linkData.position.ab, 
     stopNum: i+j, 
     fileName: linkData.title 
    }); 
    } 
    //push to json array 
    json.push(child); 
} 

//stringify the JSON and post results 
var results= JSON.stringify(json); 

然而，這並不完全工作，因爲

$post= json_decode($_POST['json']) 

PHP語句返回一個畸形的陣列其中$post.length被視爲未定義的常量。我假設這是由於格式不正確。

使用上面定義的對象，如何創建一個格式良好的JSON發送到服務器？

的stringify()當前結果是

[ 
    {"latitude":43.682211,"longitude":-70.45070499999997,"stopNum":0,"filename":"../panos/photos/1-prefix_blended_fused.jpg"}, 
    [ 
    {"latitude":43.6822,"longitude":-70.45076899999998,"stopNum":0,"fileName":"../panos/photos/2-prefix_blended_fused.jpg"} 
    ], 
    {"latitude":43.6822,"longitude":-70.45076899999998,"stopNum":1,"filename":"../panos/photos/2-prefix_blended_fused.jpg"}, 
    [ 
    {"latitude":43.68218,"longitude":-70.45088699999997,"stopNum":1,"fileName":"../panos/photos/4-prefix_blended_fused.jpg"}, 
    {"latitude":43.68218,"longitude":-70.45088699999997,"stopNum":2,"fileName":"../panos/photos/4-prefix_blended_fused.jpg"} 
    ] 
] 

而且，我使用$post.length在

$post = json_decode($POST['json']); 
for ($i=0; $i<$post.length; $i++) { } 

來迭代所處理的陣列之上。

POST請求是通過定義爲

$.ajax({ 
    type: "POST", 
    url: "../includes/phpscripts.php?action=postTour", 
    data: {"json":results}, 
    beforeSend: function(x){ 
    if (x && x.overrideMimeType){ 
     x.overrideMimeType("application/json;charset=UTF-8"); 
    } 
    }, 
    success: function(data){ 
    if (data == "success") 
     console.log("Tour update successful"); 
    else 
     console.log("Tour update failed"); 

    } 
}); 

Answer 1

這應該工作。

var json = []; 
var linkData; 
for (var i = 0; i < tourList.length; i++) { 
    var data = tourList[i]; 
    //create new child array for insertion 
    var child = [{ }]; 

    //push location marker data 
    child[0]['location'] = [{ 
     latitude: data.location.position.$a, 
     longitude: data.location.position.ab, 
     stopNum: i, 
     filename: data.location.title 
    }]; 

    child[0]['links'] = []; 

    //add associated link data 
    for (var j = 0; j < data.links.length; j++) { 
     linkData = data.links[i]; 
     child.links.push({ 
      latitude: linkData.position.$a, 
      longitude: linkData.position.ab, 
      stopNum: i + j, 
      fileName: linkData.title 
     }); 
    } 
    //push to json array 
    json.push(child); 
} 

//stringify the JSON and post results 
var results = JSON.stringify(json); 

但是，爲什麼你使輸出JSON如此複雜？更簡單的方法是使用這樣的東西：

item1: { 
    "location": { 
     "latitude": value, "longitude": value, "stopNum": value, "fileName": value 
    }, 
    "links": [ 
     {"latitude": value, "longitude": value, "stopNum": value, "fileName": value }, 
     {"latitude": value, "longitude": value, "stopNum": value, "fileName": value }, 
     {"latitude": value, "longitude": value, "stopNum": value, "fileName": value } 
    ] 
}, 
item2: [ //repeat of above ] 

你在做什麼是爲單個對象創建'數組'。爲什麼這樣做？如果使用這種格式，代碼（巧妙地）簡化了：

var json = []; 
var linkData; 
for (var i = 0; i < tourList.length; i++) { 
    var data = tourList[i]; 
    //create new child array for insertion 
    var child = { }; 

    //push location marker data 
    child.location = { 
     latitude: data.location.position.$a, 
     longitude: data.location.position.ab, 
     stopNum: i, 
     filename: data.location.title 
    }; 

    child.links = []; 

    //add associated link data 
    for (var j = 0; j < data.links.length; j++) { 
     linkData = data.links[i]; 
     child.links.push({ 
      latitude: linkData.position.$a, 
      longitude: linkData.position.ab, 
      stopNum: i + j, 
      fileName: linkData.title 
     }); 
    } 
    //push to json array 
    json.push(child); 
} 

//stringify the JSON and post results 
var results = JSON.stringify(json); 

Answer 2

答案，我的朋友，一個jQuery.ajax()功能JSON.stringfy()：

https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/JSON/stringify