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我想在我的iPhone應用程序中獲取當前城市名稱。iPhone - 從Latitude和Longtiude獲取城市名稱
我目前得到使用CLLocationManager緯度和經度和比我通過我的座標到CLGeocoder。
CLGeocoder * geoCoder = [[CLGeocoder alloc] init];
[geoCoder reverseGeocodeLocation:location completionHandler:^(NSArray *placemarks, NSError *error) {
for (CLPlacemark * placemark in placemarks) {
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Current City" message:[NSString stringWithFormat:@"Your Current City:%@",[placemark locality]] delegate:self cancelButtonTitle:@"OK" otherButtonTitles:@"Cancel", nil];
[alert show];
}
}];
這在iOS 5.0中工作正常，但在iOS 4.3中不工作。
作爲替代，我開始使用谷歌Web服務
-(void)findLocationFor:(NSString *)latitudeStr
andLontitude:(NSString *)longtitudeStr{
if ([self connectedToWiFi]){
float latitude = [latitudeStr floatValue];
float longitude = [longtitudeStr floatValue];
NSMutableDictionary *parameters = [NSMutableDictionary dictionaryWithObjectsAndKeys:
[NSString stringWithFormat:@"%f,%f", latitude, longitude], @"latlng", nil];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://maps.googleapis.com/maps/api/geocode/json"]];
[parameters setValue:@"true" forKey:@"sensor"];
[parameters setValue:[[NSLocale currentLocale] objectForKey:NSLocaleLanguageCode] forKey:@"language"];
NSMutableArray *paramStringsArray = [NSMutableArray arrayWithCapacity:[[parameters allKeys] count]];
for(NSString *key in [parameters allKeys]) {
NSObject *paramValue = [parameters valueForKey:key];
[paramStringsArray addObject:[NSString stringWithFormat:@"%@=%@", key, paramValue]];
}
NSString *paramsString = [paramStringsArray componentsJoinedByString:@"&"];
NSString *baseAddress = request.URL.absoluteString;
baseAddress = [baseAddress stringByAppendingFormat:@"?%@", paramsString];
[request setURL:[NSURL URLWithString:baseAddress]];
NSError *error = nil;
NSURLResponse *response = nil;
NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
if (response == nil) {
if (error != nil) {
}
}
else {
NSDictionary *responseDict = [returnData objectFromJSONData];
NSArray *resultsArray = [responseDict valueForKey:@"results"];
NSMutableArray *placemarksArray = [NSMutableArray arrayWithCapacity:[resultsArray count]];
for(NSDictionary *placemarkDict in resultsArray){
NSDictionary *coordinateDict = [[placemarkDict valueForKey:@"geometry"] valueForKey:@"location"];
float lat = [[coordinateDict valueForKey:@"lat"] floatValue];
float lng = [[coordinateDict valueForKey:@"lng"] floatValue];
NSMutableDictionary *dict = [[NSMutableDictionary alloc] init];
[dict setObject:[NSString stringWithFormat:@"%.f",lat] forKey:@"latitude"];
[dict setObject:[NSString stringWithFormat:@"%.f",lng] forKey:@"longitude"];
[dict setObject:[placemarkDict objectForKey:@"formatted_address"] forKey:@"address"];
[placemarksArray addObject:dict];
[dict release];
}
NSDictionary *placemark = [placemarksArray objectAtIndex:0];
}
}
}
但我正在逐漸過長，意味着我仍然無法獲得城市的名字，因爲在某些情況下，該Web服務的響應提供有關座標的所有其他信息。
任何一個能幫助我嗎？
一段時間，這段代碼不能正常工作，請儘量找一些替代的解決方案 – btmanikandan
不適合我的工作 我正在使用此http://maps.google.com/maps/geo?q=37.785834,-122.406417&output=csv 輸出爲「610,0,0,0」 –
@HardikShah你正在得到這個輸出，因爲你正在使用** csv **。將其更改爲** xml **或** json **，就像'output = xml'一樣，它會告訴您這是舊的地址解析，而新的是不同的。您還將在xml或json響應中獲得新的地理編碼鏈接。 – TheTiger