PHP Curl不存儲json_encoded回顯數據

Question

有沒有人可以存儲來自Curl腳本的回顯結果。腳本的

例已提交：捲曲的

\\some code to generate images using imagick and the post variables 

$array = array(1,2,3,4,5,6,7,8,9); 
$result = json_encode($array); 
echo $result; 

例子：

$id = 1; 
$champ = array("product" => "1","id"=> $id,"occasion"=> $o,"field1" => "1991","field2" => "test","field3" =>"test1","field4" => "test2","field5" =>"test3","field6" =>"test4","field7" =>"test5","field8" =>"test6","test7"); 
foreach($champ as $key => $data){ 
    $field_string .= $key."=".$data."&"; 
} 
rtrim($field_string, "&"); 

$url = "http://www.test.com/website/script.php"; 
$ch = curl_init(); 
curl_setopt($ch,CURLOPT_URL,$url); 
curl_setopt($ch,CURLOPT_POST, count($champ)); 
curl_setopt($ch,CURLOPT_POSTFIELDS, $field_string); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, FALSE); 
$result = curl_exec($ch); 
$array = json_decode($result); 
curl_close($ch); 
var_dump($array); 

如果我的var_dump（$結果）我得到一個布爾（真），所以我知道該腳本有執行正確，輸出顯示在屏幕上，但我似乎無法將信息存儲到變量中進行處理。

預先感謝您

Answer 1

由於curl_exec documentation說：

curl_exec() returns TRUE on success or FALSE on failure. 
However, if the CURLOPT_RETURNTRANSFER option is set, 
it will return the result on success, FALSE on failure. 

你的情況，你把CURLOPT_RETURNTRANSFER關閉。 打開它通過

curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE); 

，並再次檢查$結果。

注意：使用foreach循環和rtrim（）構建請求，如果您的數據包含&字符，則可能會損壞它。

只需使用http_build_query()與$champ：

curl_setopt($ch,CURLOPT_POSTFIELDS, http_build_query($champ));