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我做了一個程序,用戶用CenterX和CenterY座標,寬度和高度創建兩個自定義矩形。用戶指定這些尺寸後,程序將顯示一個矩形是否包含另一個矩形,與另一個矩形重疊,還是完全不符合。這裏是我的代碼:矩形重疊,但說它在裏面?
import javafx.application.Application;
import javafx.scene.Scene;
import javafx.stage.Stage;
import javafx.scene.shape.*;
import javafx.scene.text.*;
import javafx.scene.paint.Color;
import javafx.scene.layout.Pane;
import java.util.*;
public class TwoRectangles extends Application
{
public void start(Stage stage)
{
Pane pane = new Pane();
Scanner input = new Scanner(System.in);
System.out.print("Enter the X and Y center coordinates for rectangle1: ");
double xCord1 = input.nextDouble();
double yCord1 = input.nextDouble();
System.out.print("Enter the Width and Height for rectangle1: ");
double width1 = input.nextDouble();
double height1 = input.nextDouble();
System.out.print("Enter the X and Y center coordinates for rectangle2: ");
double xCord2 = input.nextDouble();
double yCord2 = input.nextDouble();
System.out.print("Enter the Width and Height for rectangle2: ");
double width2 = input.nextDouble();
double height2 = input.nextDouble();
Rectangle rectangle1 = new Rectangle(xCord1, yCord1, width1, height1);
Rectangle rectangle2 = new Rectangle(xCord2, yCord2, width2, height2);
rectangle1.setFill(null);
rectangle2.setFill(null);
rectangle1.setStroke(Color.BLACK);
rectangle2.setStroke(Color.BLACK);
// Compute the 4 corners's coordinates for the rectangle
double r1x1 = xCord1 - (width1/2.0);
double r1x2 = xCord1 + (width1/2.0);
double r1y1 = yCord1 + (height1/2.0);
double r1y2 = yCord1 - (height1/2.0);
double r2x1 = xCord2 - (width2/2.0);
double r2x2 = xCord2 + (width2/2.0);
double r2y1 = yCord2 + (height2/2.0);
double r2y2 = yCord2 - (height2/2.0);
if ((r1x1 >= r2x1) && (r1x2 <= r2x2) && (r1y1 >= r2y1) && (r1y2 <= r2y2))
{
Text containText = new Text(500, 500, "One rectangle is contained in another");
pane.getChildren().add(containText);
}
else if ((r1x1 < r2x2) && (r1x2 > r2x1) && (r1y1 < r2y2) && (r1y2 > r2y1))
{
Text overlapText = new Text(500, 500, "The rectangles overlap");
pane.getChildren().add(overlapText);
}
else
{
Text noneText = new Text(500, 500, "The rectangles do not overlap");
pane.getChildren().add(noneText);
}
pane.getChildren().addAll(rectangle1, rectangle2);
Scene scene = new Scene(pane);
stage.setTitle("Overlapping Rectangles");
stage.setScene(scene);
stage.show();
}
}
每當我進入,(50,50)的centerX和centerY座標兩個矩形,寬度:20,爲rectangle1高度50和寬度50,爲rectangle2高度20它告訴我矩形在彼此內部而不是彼此重疊。我究竟做錯了什麼?
我要說的是,計算有錯誤'雙r1y1 = yCord1 +(height1/2.0);'必須'雙r1y1 = yCord1 - (height1/2.0);'和類似的'雙r1y2 = yCord1 +(height1/2.0);'和r2y1和r2y2以及 – ItachiUchiha
@IchichiUchiha通常是的,但是當你繪畫的東西,它可以更好另一種方法。 – maraca
@IchichiUchiha我把我的第一個條件改爲你的條件,但我仍然得到相同的錯誤 – Bytes