我正在創建一個應用程序,它首先通過檢查SQLite數據庫中的數據來檢查用戶是否有效。我在數據庫中創建了一個名爲loginchk
的表,其中有三行兩列,分別爲uname
和pass
。從SQLite數據庫獲取比第一行多的問題
當我運行應用程序並在我的文本字段中輸入用戶名和密碼值時,它會檢查用戶名和密碼是否在數據庫中。如果不是,則會顯示一個警告視圖,顯示「請輸入正確的用戶名」。
在我的代碼中存在一個問題:它只讀取第一行,即當我輸入第一行成功的用戶名和密碼值,並且我輸入的所有其他值都不起作用。
可能是什麼問題?
謝謝。
#import "loginAppDelegate.h"
#import "global.h"
#import <sqlite3.h>
#import "logincontroller.h"
@implementation loginAppDelegate
@synthesize window;
@synthesize loginView;
//[email protected]"login.sqlite";
-(void) chekAndCreateDatabase
{
BOOL success;
//sqlite3 *[email protected]"login.sqlite";
NSFileManager *fileManager=[NSFileManager defaultManager];
NSArray *documentPaths=NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
NSString *documentsDir =[documentPaths objectAtIndex:0];
NSString *databasePath=[documentsDir stringByAppendingPathComponent"login.sqlite"]; success=[fileManager fileExistsAtPathatabasePath];
if(success)return;
NSString *databasePathFromApp=[[[NSBundle mainBundle]resourcePath]stringByAppendingPathComponent"login.sqlite"];
[fileManager copyItemAtPathatabasePathFromApp toPathatabasePath error:nil]; [fileManager release];
}
-(void) Data
{
[email protected]"";
[email protected]"";
sqlite3_stmt *detailStmt=nil;
//sqlite3 *databaseName;
NSArray *documentPaths=NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
NSString *documentsDir =[documentPaths objectAtIndex:0];
NSString *databasePath=[documentsDir stringByAppendingPathComponent{angry_smile}"login.sqlite"];
[self chekAndCreateDatabase];
sqlite3 *database;
if (sqlite3_open([databasePath UTF8String],&database)==SQLITE_OK)
{
if (detailStmt==nil)
{
const char *sql= "select *from Loginchk"; //where uname='%?'and password='%?'"; //NSString *sql = [[NSString alloc] initWithFormat{angry_smile}"SELECT * FROM Loginchk WHERE uname ='%@' and password ='%@' ",Uname.text,Password.text];
if (sqlite3_prepare_v2(database,sql,-1,&detailStmt,NULL)==SQLITE_OK)
{
sqlite3_bind_text(detailStmt,1,[Gunameq UTF8String],-1,SQLITE_TRANSIENT);
sqlite3_bind_text(detailStmt,2,[Gpassq UTF8String],-1,SQLITE_TRANSIENT);
if (SQLITE_DONE!= sqlite3_step(detailStmt))
{
Guname=[NSString stringWithUTF8Stringchar*)sqlite3_column_text(detailStmt,0)];
Gpass =[NSString stringWithUTF8Stringchar*)sqlite3_column_text(detailStmt,1)];
NSLog(@"'%@'",Guname);
NSLog(@"'%@'",Gpass); }
} sqlite3_finalize(detailStmt);
}
} sqlite3_close(database);
}
這是我的登錄控制器;在這裏,我打電話給我的應用程序委託的功能data
:
-(IBAction)buttonPressed:(id)sender
{
Gpassq=Password.text;
Gunameq=Uname.text;
NSLog(@"%@%@",Gunameq,Gpassq);
loginAppDelegate *appDelegate =(loginAppDelegate *)[[UIApplication sharedApplication]delegate];
[appDelegate Data];
if ([Uname.text isEqualToString:Guname]&&[Password.text isEqualToString:Gpass])
{
UIAlertView *alert=[[UIAlertView alloc]initWithTitle:@"UIAlertView" message:@"Success" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
[alert release];
}
else
{
UIAlertView *alert =[[UIAlertView alloc]initWithTitle:@"UIAlertView" message:@"PleaseEnterCorrectUserName and password" delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];
[alert show];
[alert release];
}
}
如果去除,並添加,而不是檢查我的病情直接進入else部分 – Rani 2011-04-14 11:01:20
你確定你在你的數據庫中的多行..打印數據庫的路徑和開放它使用一些SQLite客戶端,並檢查表.. – Saurabh 2011-04-14 11:11:12
我不能相信這是行不通的..我測試了這個代碼!你一定有其他問題! – Saurabh 2011-04-14 11:46:35